Boolean Algebra Toolbox is a small set of functions for easy generation of boolean nbc and gray sequences for sets of boolean variables.
[X1 X2...]=NBC(N) will generate a table of Natural Binary Code where the output is a set of bool-objects.
[X1 X2 X3]=NBC(3) yields:
» [x1 x2 x3]=nbc(3)
and BGRAY(3) yields:
» [x1 x2 x3]=grayc(3)
The constructor for the bool-class works as this:
» x=bool([1 inf 0 -1 0 nan])
of course, the constructor can also have a bool object as an argument.
B2H(X) is a function which converts a binary vector to hex string (length(X)=2^n is required).
The operators used are
+ : or
| : or
* : and
& : and
~ : not
' : not
/ : xor
you can use inequalities as well:
< > <= >= == ~=
some functions used by the bool class:
b2d : "bool" to decimal
b2h : "bool" to hex
display : display object
double : convert to double array
flip : flip the entire boolean object string
flip4 : flips the overall nibble position
flip4i : flips the bit positions for each nibble
flip8 : same as flip4 but for bytes
flip8i : same as flip4i but for bytes
horzcat : bit string concatenation, works with mixed objects (as [0 x1 1 nan x2])
length : length of the bit-string/bool-object
size : size of object in bits, nibbles, bytes, words, etc... depending on structure.
subsasgn : assign with indicies
subsref : pick out bits from the object string with indicies (subscripted reference).
Last but not least, the truth-table function which displays the truth-table for a boolean function with its set of variables. For instance:
» [x1 x2 x3]=nbc(3);
| x1 x2 x3 | func(*) |
| 0 0 0 | 1 |
| 1 0 0 | 0 |
| 0 1 0 | 1 |
| 1 1 0 | 0 |
| 0 0 1 | 0 |
| 1 0 1 | 1 |
| 0 1 1 | 1 |
| 1 1 1 | 1 |
I know that there might be some strange stuff goin on with the order (little/big endian a.s.o.), which is one of the reasons I implemented the flip-functions.
Please mail me for suggestions of if you encounter any problems!
More toolboxes can be found at:
Hi - don't know what might have changed between 2007, the time of the last previous post, and R2010B that I'm using but I had add the following islogical() clause to the end of bool.m
error('Input must be numeric.')
Without this change an expression such as:
I could correct the code (I found that Rasmus is no longer at the email address given) but I'm new to Matlab and am now sure what the protocol is.
It is very useful and saves me a few days to get the idea to program the same functions. Thank you.
could perhaps stand a little bit of tidying up but otherwise VERY useful. Saved me about a weeks work on my dissertation by generating grey code for me.
de Morgan's theorem is easy to test:
In both cases matlab will respond with bool object "1".
how to work boolean algebra and demargins therem, it sames confusing.
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