View License

Download apps, toolboxes, and other File Exchange content using Add-On Explorer in MATLAB.

» Watch video

Highlights from
Runge Kutta 4th order ode

Join the 15-year community celebration.

Play games and win prizes!

» Learn more

4.66667
4.7 | 7 ratings Rate this file 53 Downloads (last 30 days) File Size: 1.32 KB File ID: #29851 Version: 1.4

Runge Kutta 4th order ode

by

Judah S (view profile)

 

29 Dec 2010 (Updated )

solves ode using 4th order Runge Kutta method

| Watch this File

File Information
Description

This code defines an existing function and step size which you can change as per requirement.

P.S: This code has no new feature compared to existing codes available online. Intention behind posting this very simple code is to help students understand the concept and solve assignments.

Acknowledgements

This file inspired Ode4 Gives More Accurate Results Than Ode45, Ode23, Ode23s.

MATLAB release MATLAB 7.10 (R2010a)
Tags for This File   Please login to tag files.
Please login to add a comment or rating.
Comments and Ratings (13)
22 Aug 2016 Tareque Hossain

how can i solve SIR model using RK4 method in matlab? can you write the code please

Comment only
25 Jan 2016 faiz islam

sir can you assist me ,that how we can apply 4th order Runge kutta method for 4 coupled equation?
dx/dt=−ax − eω + yz
dy/dt= by + xz
dz/dt= cz + fω − xy
dω/dt = dω – gz
a = 50, b =−16, c = 10, d = 0.2, e = 10, f = 16, g = 0.5
Step size 0.001 .
regards
faiz

Comment only
16 Dec 2015 Ali Abbas

@Shahzaib Asif Very helpful program.JazakAllah

Comment only
10 Dec 2015 Stephanie Valerio

How do I run/call to this code?

Comment only
22 Nov 2015 Hamza Fokraoui

for this function : f'''' - f*f''' + 4*g = 0
where i need to insert it in this code?
thank you

Comment only
29 May 2015 Shahzaib Asif

function RK4(f,a,x0,y0,h)

% Runge Kutta Method 4th Order
% function @(x,y) e.g. f=@(x,y)(x+y);
% a = the point up to which you obtain the results
% x0 = initial condition of x
% y0 = initial condition of y
% step size

x = x0:h:a;
y(1) = y0;

for i=1:(length(x)-1)

k1 = f(x(i),y(i));
k2 = f(x(i)+0.5*h,y(i)+0.5*h*k1);
k3 = f((x(i)+0.5*h),(y(i)+0.5*h*k2));
k4 = f((x(i)+h),(y(i)+k3*h));

y(i+1) = y(i) + (1/6)*(k1+2*k2+2*k3+k4)*h;

end

y(:)

%Shahzaib Asif (zaibi7402)
%shahzaib.7402@gmail.com

Comment only
25 Nov 2014 Chris FUNG

clear coding

13 Mar 2013 Christoph  
04 Oct 2012 Ying

Ying (view profile)

 
04 Oct 2012 Ying

Ying (view profile)

Very good to learn. Thanks.

05 Feb 2012 Arun

Arun (view profile)

 
29 Mar 2011 Pi Ting

excellent work

02 Jan 2011 Ido

Ido (view profile)

Excellent program,
very helpful.

Updates
25 Jan 2012 1.1

Nothing much

16 Jan 2013 1.4

Just an update

Contact us