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Concatenation of arbitrarily sized data along any dimension.

Updated

M = CATPAD(dim,A1, A2, A3, ..., AN) concatenates along the dimension
DIM the arrays A1 through AN into one large matrix. The vectors do
not need to have the same size, nor number of dimensions. The size
of the output M is determined by the dimmention of concatenation,
and the size of the inputs. Any inputs that are not the correct
size will be padded with NaNs if the inputs are numeric. If they
are strings, they will be padded with a space " ".

specified by PADVAL. The default is NaN for numeric inputs, and a
space " " for string inputs.

[M TF] = CATPAD(...) outputs ana array of logicals TF having true
values when the values in that position of M were from the original

Examples:
a = 1:4; b = 1:5; c = []; d = 1:3; dim = 1;
M =
1 2 3 4 NaN
1 2 3 4 5
1 2 3 NaN NaN
% Note: The input "c" was empty, and therefore doesn't require it's
% own row.

a = rand(3); b = magic(5); c = rand([4 5 4]); dim = 3;
size(M)
5 5 6

str1 = 'What do you think of this function?';
str2 = 'I like it!';
dim = 1;
M =
What do you think of this function?
I like it!

Example: Find original NaNs
a = 1:3; b = [2:5 NaN]; c = [1 NaN]; dim = 1;
% find the original NaN
[row,col] = find(tf & isnan(M))
% -> row = [3 2] , col = [2 5]

a = 1:3; b = 1; c = 1:4; dim = 1; padval = inf;
M =
1 2 3 Inf
1 Inf Inf Inf
1 2 3 4

By Jonathan Sullian - October 2011

Many thanks to Michael Völker for his function sub2allind which has made
this function possible. Also, I would like to aknowledge Jos (10584)
whose submission padcat has inspired this one.

Sebastien Herbert

### Sebastien Herbert (view profile)

Hi, thanks a lot for your contribution! I am working with rather larger matrices and would like to change the output to uint16 instead of double. Is there a way for me to do it?

Pravin Prame Kumar

### Pravin Prame Kumar (view profile)

Thanks for this :)

Sebastien Herbert

bugguts99

Santhan Salai

Christian

### Christian (view profile)

This is really great work. Thanks for your kind contribution.

Dan K

Ivo

Heather

### Heather (view profile)

I second Harold's sentiment.

Harold Bell

### Harold Bell (view profile)

I just want to say that this function AWESOME.

Mike Sheppard