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Turbo Code

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Turbo Code

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11 Dec 2012 (Updated )

Encoding: RSC, Decoding: BCJR

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Description

Modulation: BPSK
Channel: AWGN
Encoder: G(D)=[1,(1+D+D^2)/(1+D^2)]

Required Products Communications System Toolbox
MATLAB
MATLAB release MATLAB 8.1 (R2013a)
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Comments and Ratings (75)
17 Jun 2015 Yogesh K Soniwal

Hi Younes and Krishna

You can download source code from "Download Zip" link on top right corner of this page.

Thanks
Yogesh

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17 Jun 2015 Yogesh K Soniwal

Hi Donny

I have not written Turbo code for QPSK modulation. You can refer to

http://in.mathworks.com/matlabcentral/fileexchange/39847-qpsk-performance-comparison-for-wireline-and-wireless-channel/content/qpsk.m

for implementing Turbo code for QPSK modulation.

Thanks
Yogesh

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16 Jun 2015 Kok Ann Donny

hi Yogesh and Joy,

Can u send me the source code with adaptation of QPSK modulation?
teo_kok_ann@hotmail.com

Thanks,
Donny

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15 Jun 2015 younes aimer

hi yogesh,
can u send me the source code...
younesaimer@gmail.com
thanks,
Younes

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07 Jun 2015 western  
21 Apr 2015 saikrishna jawajiwar

hi yogesh,
can u send me the source code...

thanks,
krishna.

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02 Mar 2015 joy lobo

I think the iitk mail id might be defunct now...and yogeshsoniwal@gmail.com is not being recognised...please tell me as to how to send u the code

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02 Mar 2015 joy lobo

Hey Yogesh,I have sent the code to ysoniwal@iitk.ac.in.Please check

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02 Mar 2015 joy lobo

Yogesh,whats your email id?yogeshsoniwal@gmail.com is not getting accepted

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01 Mar 2015 bilo

bilo (view profile)

Hi Yogesh
Thank you for useful source code but can you , but sir i have question about your code :
- how i can adapt your code in 4-QAM case.
(for my modulator and demodulator please refer to this source code Matlab :
n = 3e4; % Number of bits to process
M=4; % Size of signal constellation
hMod = modem.qammod(M); % Create a 4-QAM modulator
hMod.InputType = 'Bit'; % Accept bits as inputs
hMod.SymbolOrder = 'Gray'; % Accept bits as inputs
hDemod = modem.qamdemod(hMod); % Create a 4-QAM based on the modulator
% Modulate data :
x = randi([0 1],n,1); % Random binary data stream
tx = modulate(hMod,x);
% at receiver side :
rx_demod = demodulate(hDemod,tx);

28 Feb 2015 Yogesh K Soniwal

Hi Joy

Can you send me your code for QPSK.

Thanks
Yogesh

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24 Feb 2015 joy lobo

Hi Yogesh,
Following what u have done for bpsk,i have written the code for qpsk ...but the results are not as per expected...i have two questions:a)Can we do the decoding for the two bits in qpsk independently of each other,exactly identical to bpsk?That is the alpha beta calculations will be the same but only in the calculation of gamma,there will be two aprioris because the two bits are independent...?Or will the two bits interfere with each other?According to me,they wont because they lie on separate axes
b)After LLR computation,how will the decision be taken i.e.will the bit error rate be given by ber(k,iter)=sum(abs(decoded_bits1-SystematicBits1)+abs(decoded_bits2-SystematicBits2)) where SystematicBits indicate two different bit streams?
I would really appreciate some help as I am not getting the expected results...or if u have the code for this ,will u be so kind as to share it?
Thanks
J Lobo

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23 Feb 2015 Yogesh K Soniwal

Hi Ana

Please ping me on yogeshsoniwal@gmail.com. I'll send you the code.

Thanks
Yogesh

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22 Feb 2015 Ana Oliveira

Hi Yogesh,

Could you please share a code for RSC with rate 1/2?

Thanks
Ana

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21 Feb 2015 Yogesh K Soniwal

Hi Ana

Yes, the RSC has rate 1/3. As there is one information bit and the codeword is of length 3 (X, P0 and P1).

Thanks
Yogesh

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21 Feb 2015 Ana Oliveira

Hi,

Could you please tell me if the RSC used has rate 1/3?

Thanks
Ana

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16 Feb 2015 Yogesh K Soniwal

Hi Joydeep

For state transitions please refer to

http://home.iitk.ac.in/~ysoniwal/Term_Paper_Reports/EE624.pdf

For QPSK part read comments.

Thanks
Yogesh

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26 Jan 2015 joydeep bhattacharya

Hi Yogesh,
Can you let me know how you got to know about how the states are occuring?i.e.how does transition occur between the states?Also,how will it change in case of Qpsk?Thanks in advance

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11 Jan 2015 Yogesh K Soniwal

Hi popeye,

If you want to write the code for QPSK modulation, you'll have to change it starting from information bit generation. As you have to send two bit streams.

Then you'll have to decode the modulated bits using BCJR decoder. The formula for BER will also change.

Please refer to

http://in.mathworks.com/matlabcentral/fileexchange/39847-qpsk-performance-comparison-for-wireline-and-wireless-channel/content/qpsk.m

Thanks
Yogesh

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11 Jan 2015 Yogesh K Soniwal

Dear Keyvan,

The alpha and beta values are not wrong. If you read the comment of these functions, it says." Each column is for states 00,10,01 and 11 RESPECTIVELY".

They are NOT in 00, 01, 10 and 11 order.

Thanks
Yogesh

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07 Jan 2015 popeye

popeye (view profile)

Hi Yogesh,

Your code is clear for me, but I have questions as follows:
1. I want to use a higher order modulation like QPSK or 16QAM. So, in the receiver, the received signal should be passed through demapper block first. Then, we get the values of LLR_demapper (soft demodulation), which becomes the input for the turbo decoder. My point here is, at the moment, the input of turbo decoder is not the original received signal, some parameters in your code should be changed right ? Like, channel reliability, etc. How we can do it ?

2. Just a comment. I do agree with the guy who ask you about using 1/sqrt(2*1/3*SNR) instead of 1/sqrt(2*SNR) as in your code.

Hope to receive your reply soon,
Cheers

30 Dec 2014 Keyvan Shahin

Hi Dear Yogesh,
I am trying to generalize your code for a 16 state code, but I have a problem with your alpha and beta functions, I think they are wrong, but the result is right, and I'm confused a little. I would appreciate if you would help me with this:
first as I look at the trellis and the gamma(1:4, 1:2) and I think alpha and beta should be like this:
ALPHA(1,i)=((GAMMA(1,j)*ALPHA(1,i-1))+(GAMMA(3,j)*ALPHA(3,i-1)));
ALPHA(2,i)=((GAMMA(3,j+1)*ALPHA(3,i-1))+(GAMMA(1,j+1)*ALPHA(1,i-1)));
ALPHA(3,i)=((GAMMA(2,j)*ALPHA(2,i-1))+(GAMMA(4,j)*ALPHA(4,i-1)));
ALPHA(4,i)=((GAMMA(4,j+1)*ALPHA(4,i-1))+(GAMMA(2,j+1)*ALPHA(2,i-1)));

BETA(1,i)=(GAMMA(1,j)*BETA(1,i+1))+(GAMMA(1,j+1)*BETA(2,i+1));
BETA(2,i)=(GAMMA(2,j)*BETA(3,i+1))+(GAMMA(2,j+1)*BETA(4,i+1));
BETA(3,i)=(GAMMA(3,j+1)*BETA(2,i+1))+(GAMMA(3,j)*BETA(1,i+1));
BETA(4,i)=(GAMMA(4,j+1)*BETA(4,i+1))+(GAMMA(4,j)*BETA(3,i+1));

if you could help what am I doing wrong.
ty very much. and ty for your simple and well written code.

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25 Nov 2014 Yogesh K Soniwal

C0 is same as P0, and C1 is same as P1. Maybe the notation is a bit confusing.

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24 Nov 2014 Gamma

Gamma (view profile)

thanks a lot..
one small quastion,,in your code of encoder u r calculating in loop C0 and C1 and with this C0 and C1 you are calculating Po ans P1..its clear..but at which stage of Encoder diagram you r calculating co and c1?this is not so clear for me--i mean after feedback value and input or where ?
can u plz clear it..i will be thankful t u.

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21 Nov 2014 Yogesh K Soniwal

Please refer

http://paginas.fe.up.pt/~sam/textos/From%20BCJR%20to%20turbo.pdf

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17 Nov 2014 Gamma

Gamma (view profile)

thanks Yogesh..i habe read this paper..its good..but can u tell me from which BOOK you have used this formula...i mean Reference of Book or any paper..
and how u demodelate your singal,because R0,R1 R2 are demodulated...'?
thanks

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14 Nov 2014 Yogesh K Soniwal

Hi Muhammad

Please refer to

http://home.iitk.ac.in/~ysoniwal/Term_Paper_Reports/EE624.pdf

for formulae of alpha, beta and gamma

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11 Nov 2014 Kondakov  
05 Nov 2014 Gamma

Gamma (view profile)

Hi,Yogesh

i have seen ur code and also paper,i hava quastion how u demodelate your singal,because R0,R1 R2 are demodulated but which formula are u using?

and the formula for calculating gamma?where did u got this i mean can u share any reference file.thanks in advance.

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03 Jul 2014 Sanchis

Hi Yogesh,

your code is very well!! But there is a thing that I don't understand and it is: I don't understand as you encode P1 and P0. I have readed the description in page 2 and 3 of your paper, but I don't understand, Could you explain me it? And as you implements it in the code?

Thanks you.

01 May 2014 Yogesh K Soniwal

Hi Long
I have not checked if there is any difference in the performance if we use extrinsic information.
If you want to use extrinsic information, just substract the intrinsic term given on page 4 of
http://home.iitk.ac.in/~ysoniwal/Term_Paper_Reports/EE624.pdf
from aposteriori information.

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15 Apr 2014 popeye

popeye (view profile)

Hi Yogesh,

As from your code, the information you exchanged between two decoders is the a-posteriori information not extrinsic information as in theory. Is there any difference in the performance ? If I want to use extrinsic information in this case, how I can ? Thanks.

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27 Mar 2014 Yogesh K Soniwal

Hi Tongyang
In BCJR decoder we exclude the intrinsic information and pass the aposteriori probability from one decoder to another for subsequent detection

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13 Mar 2014 tongyang

from your PDF report, you mentioned that only extrinsic information is exchanged between two BCJR decoders. However, in your MATLAB code, I think the exchanged information is the a-posteriori information. Is it correct? Thanks.

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12 Mar 2014 Yogesh K Soniwal

yes

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05 Mar 2014 mary

mary (view profile)

hi.. is the used interleaver a random permutation interleaver?

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17 Feb 2014 Filip

Filip (view profile)

Yogesh, you should divide the SNR by 3 because the SNR is defined with respect to the energy per information bit (Eb), and not per coded bit (Es). This code has a rate of 1/3, right? Therefore, you need to consider the code rate when you corrupt the signal by noise.
Eb/No=(1/rate)*Es/No = (1/rate)*(mu^2)/(2*sigma^2)

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15 Feb 2014 Yogesh K Soniwal

Hi Filip
I don't think there is any problem in scaling. Why would you divide the SNR in all 3 bits?

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13 Feb 2014 Filip

Filip (view profile)

One little correction ,should be 2*1/3*SNR, I forgot the factor 2.

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13 Feb 2014 Filip

Filip (view profile)

Hey Yogesh. Are you sure the SNR scaling is correct in the turbo.m file? You assume a certain SNR, but you apply the same value to R0, R1 and R2, which is incorrect because you have not considered the code rate. The correct thing would be the following: instead

R0=sqrt(SNR(k))*mod_code_bit0+randn(1,N);

you should have written

R0=sqrt(1/3*SNR(k))*mod_code_bit0+randn(1,N);

because your code rate is 1/3.
By doing as you did the corruption is very less and your output BER is smaller.

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26 Jan 2014 devina etwara

Hi Yogesh.. i have an something to ask. actually whenever i'm increasing the snr gap, that is i'm changing it to 0.2 interval.. i am getting peaks .. like the graphs is shooting up and then coming down.. i wanted to know that is normal behaviour of turbo codes... i am getting little confused and even getting stressed as i am using your code as my base start for my dissertation .. please do lemme know about it.. please i am hope to hear from you soon

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06 Jan 2014 wang jack  
05 Dec 2013 mary

mary (view profile)

hi yogesh,
let's suppose that i have value "A"
I want to multiply the encoded data by it and than add noise then dividing the result by the same value then decode the resulting data:
suppose my data is X , and nose is N;
I want to do the following

s=X.*A
then add noise ss=s+N
then the data that will be decoded=ss./A

can you do that to your code??

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11 Nov 2013 Yogesh K Soniwal

Hi Jang,
Please refer to page No. 5 for alpha and page No. 9 for (j+2) in this link
http://home.iitk.ac.in/~ysoniwal/Term_Paper_Reports/EE624.pdf

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11 Nov 2013 jang

jang (view profile)

I do not know how the alpha is defined.
Also, j +2, why are you used?

24 Oct 2013 Yogesh K Soniwal

Sravya,
Download all the codes in one directory then run turbo.m

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24 Oct 2013 sravya

sravya (view profile)

Error in turbo (line 43)
dlg = ProgressDialog();
i got this error when i simulated it please help me in this.. thanq...

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18 Sep 2013 ANAND

ANAND (view profile)

hello sir...
am doing project in increasing energy efficiency using turbo code.... i calculated Eb value for BPSK modulation... have to substitute the Eb value in turbo code.... how can i do it....
plz give me your ans to my mail id:
edalanand@gmail.com

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17 Sep 2013 Yogesh K Soniwal

The interleaver used in this code is random (line no. 4 of turbo.m) .. replace your designed interleaver with this one.

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17 Sep 2013 mustafa

HELLO SIR
your work is really perfect and i am concerned with the interleaver how can i replace the existing interleaver by my designed interleaver?

31 Jul 2013 vahid

vahid (view profile)

hi tank u for ur code.the decoder depends on the snr but in reallity we dont know the snr how can we implement this code ?

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03 Jul 2013 triet ho

why only has 3rd iteration? i saw picture has 4th iteration? can you update iteration higher? tks so much. can you send your updated code to my email: hobaominhtriet@gmail.com. tks you.

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28 Jun 2013 Yogesh K Soniwal

You can refer to code provided on this link for 16-QAM
http://www.dsplog.com/2007/12/09/symbol-error-rate-for-16-qam/

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25 Jun 2013 DUJIN KWON

If I want to modify your program by using 16qam modulation instead of BPSK can you help me with that?

13 Jun 2013 Yogesh K Soniwal

no..performance for QPSK and BPSK will be different

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12 Jun 2013 mary

mary (view profile)

will the performance be better when using QPSK modulation?? or it will be the same as when using BPSK?

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12 Jun 2013 mary

mary (view profile)

Do you have a matlab code of it ? Can you do it for me please?

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12 Jun 2013 Yogesh K Soniwal

You have to transmit 2 bits for each symbol. And decode each of them individually. Refer to the QPSK simulation code.

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11 Jun 2013 mary

mary (view profile)

If I want to modify your program by using QPSK modulation instead of BPSK can you help me with that?

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11 Jun 2013 Yogesh K Soniwal

Yes, the modulation used is BPSK.

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10 Jun 2013 mary

mary (view profile)

another question i have >> the modulating you are using is BPSK right???

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10 Jun 2013 mary

mary (view profile)

 
10 Jun 2013 mary

mary (view profile)

i mean can we make the first RSC encoder of rate 2/3 ?? so according to this the second encoder will also be of rate 2/3

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09 Jun 2013 Yogesh K Soniwal

no..we are using the same bits permuted for the second RSC encoder, so we can't make this code rate 2/3.

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09 Jun 2013 mary

mary (view profile)

So it means that to make it of rate 2/3 we should use two bits as an input to RSC encoders right? Is it possible with BCJR decoding?

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09 Jun 2013 Yogesh K Soniwal

There are two encoders. Information bits are coded using convolution code for the first encoder and their permutation is coded using convolution code for the second encoder, but only one bit is used for second encoder. So RSC encoder is rate 1/3.

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08 Jun 2013 mary

mary (view profile)

okay and what about the bit rate of the RSC encoders??

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05 Jun 2013 mary

mary (view profile)

okay thank you

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15 May 2013 Yogesh K Soniwal

Hi mary,
this is rate 1/3 code..

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15 May 2013 mary

mary (view profile)

what is the bit rate of this encoder please??

05 May 2013 saikiran

Hi, In the code when we increase block length the performance of the code should be increased in ber wise. But it is not the case happening?

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29 Apr 2013 mary

mary (view profile)

or it is of 8 states?

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29 Apr 2013 mary

mary (view profile)

okay it ran thank you

well this code is of 4 states trellis could you make it of 8 states ??

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28 Apr 2013 Yogesh K Soniwal

You have not downloaded 'parity_bit' function which is used by turbo.m . That's why this error is coming. Download all the other functions (alpha_1, beta_1,gamma_1, parity_bit, lappr) and then run turbo.m

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28 Apr 2013 mary

mary (view profile)

hello
when i ran it using matlab 2012 an error occured
"Undefined function 'parity_bit' for input arguments of type
'double'." what do i do?

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Updates
30 Jul 2013 1.1

Iterations increased for better performance

17 Oct 2013 1.2

Encoding not done iteratively, used convolution for encoding

22 Oct 2013 1.3

Fixed Error in UI

31 Oct 2014 1.4

Submitted as a toolbox

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