Plot 2D/3D region

The program plots convex closed regions in 2D/3D.

Description

The program plots convex closed regions in 2D/3D. The region is a subset of R2 or R3 such that Ax>=b and lb<=x<=ub. It is also possible to plot points in the same plot.

(See help plotregion for more documentation)

• MATLAB release: MATLAB 6.0 (R12)

[John D'Errico]

Splendid. A very nice utility that I'll happily use. I'd have
liked more documentation in the help, but I tend to go
overboard there myself, so my standards may be deemed
excessive by sane, rational beings. The examples were
enough to figure it out.

[Peter Larsen]

Just what I needed. Thanks.

[Amir Ali Ahmadi]

After hours of playing around with different m-files, trying to figure out how to fill the region b/w the intersection of some planes in R^3, I found this m-file which took care of the job in less than a minute.

Matlab has a built-in function ?area? for 2-D but nothing for 3-D (to my understanding).

I used plotregion.m to visualize a subset of R^3 where all the vectors have norm-1 less than say 3. (i.e. abs(x)+abs(y)+abs(z)<=3). This is easily done using this m-file by inputting an 8x3 constraint matrix A.

Thanks a lot & great work?

-AAA

[a a]

 

[mc k]

 

[Golnaz Habibi]

 

[E. Hearn]

I am sure this works well, but it needs clearer documentation. I simply cannot understand the format.
"The region(s) x is a subset of R2/R3 s.t. A*x>=b and lb<=x<=ub" is rather cryptic.

[PA L]

interesting

[Steven Randolph]

 

[Jianing Di]

I think it is very useful.

[Juan Carlos Trillo]

I was looking for something similar, great!
Only one question, how can one do to appropiately define the planes to plot general closed regions?

[Thierry Dalon]

Good contribution!

[Rodrigo Lopez]

very good! just what i need for my thesis. Thanks!

Juan Carlos: You can close your polyhedron by adding goods upper and lower bounds.

[Magnus]

Thanks for a nice package - it saved me quite some time! A hint to users: You get the error "Vector must have 4, 6, or 8 elements." if you specify an unfeasible set, i.e. if your A and b are such that no x fulfill Ax >= b. In my case, it was because I happened to define the normal vectors so they point out instead of in, i.e., the sign of A was reversed.