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Madi

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04 Apr 2013 Feature Extraction Using Multisignal Wavelet Packet Decomposition Its simply a feature extraction code using the Wavelet Packet Transform (WPT). Author: Dr. Rami Khushaba

Thank you for the comment.. I just concern It should be same answer for 'feat' at Approximate coefficient.. From the example you given, YES the answer are same.. when I go through the code (getmswtfeat.m) It is look like different in how to determine the last answer.. for code (getmswpfeatV00.m).. I can understand the flow.. but for the 'getmswtfeat.m', I'm confused for term 'percentENER(notZER,:) = ...', '[cfs,longs] = wdec2cl(dec,'all')',.. and I hope the final answer for 'tab_ENER' should be same as WP code... sorry to many question...

04 Apr 2013 Feature Extraction Using Multisignal Wavelet Packet Decomposition Its simply a feature extraction code using the Wavelet Packet Transform (WPT). Author: Dr. Rami Khushaba

Thank You Dr Rami,

I tried the code (getmswtfeat.m (Your WT code)) and try to remove and maintain 'log1p'.. the result for 'energy' approximate coefficient are different when using the code (getmswpfeatV00.m)..

04 Apr 2013 Feature Extraction Using Multisignal Wavelet Packet Decomposition Its simply a feature extraction code using the Wavelet Packet Transform (WPT). Author: Dr. Rami Khushaba

Thank you for reply..I understand now..

If I run this code (getmswpfeatV00.m) and I only took the energy at approximation part (Low pass filter part).. It is the result will be same if I'm using this code (getmswtfeat.m (Your WT code))?

One more thing, actually the code below is for what? Because you said can comment it.. If I comment this code the result is different.

I test for J=1 and comment the code below and I compare with using this code ([CA,CD] = dwt(xx,'sym8');) and took the energy for CA and CD.. and the result is same.

%% You can comment this section
JJ = J;
for i=1:J-1
T = (2^i):(2^i)+(2^i)-1;
feat(:,T) = feat(:,T)./log(JJ);
JJ=JJ-1;
end

04 Apr 2013 Feature Extraction Using Multisignal Wavelet Packet Decomposition Its simply a feature extraction code using the Wavelet Packet Transform (WPT). Author: Dr. Rami Khushaba

Dear Dr Rami,

I'm new in Wavelet Feature extraction, I have two question: :)

1) just to ask what is the different Wavelet Packet Decomposition and Wavelet Transform Decomposition?

2) From you code, feat = WPT features (compete tree without node selection).. actually what is WPT features?.. It is energy based? or median or mean?

Thank You

25 Jan 2013 MyFriedman Friedman test for non parametric two way ANalysis Of VAriance Author: Giuseppe Cardillo

Nemenyi test (alpha == 0.05):

qalpha = [0.000 1.960 2.344 2.569 2.728 2.850 2.948 3.031 3.102 3.164 ...
3.219 3.268 3.313 3.354 3.391 3.426 3.458 3.489 3.517 3.544 ...
3.569 3.593 3.616 3.637 3.658 3.678 3.696 3.714 3.732 3.749 ...
3.765 3.780 3.795 3.810 3.824 3.837 3.850 3.863 3.876 3.888 ...
3.899 3.911 3.922 3.933 3.943 3.954 3.964 3.973 3.983 3.992 ...
4.001 4.009 4.017 4.025 4.032 4.040 4.046];

Then replace cv inside the code with:

cd = qalpha(k)*sqrt(k*(k+1)/(6*b));

So here we get cv using Nemenyi Test.

Please Advice.

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