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Daniel Zoran

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Company/University: Hebrew University of Jerusalem

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Comments and Ratings by Daniel		View all 1 - 2 of 2
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09 Feb 2011	EM algorithm for Gaussian mixture model EM algorithm for Gaussian mixture. Works on arbitray dimensions with high speed and precision. Author: Michael Chen
12 Oct 2009	graphViz4Matlab Display a directed or undirected graph in a Matlab figure window. Author: Matt Dunham

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File	kernel density estimation

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26 May 2009		kernel density estimation fast and accurate state-of-the-art bivariate kernel density estimator Author: Zdravko Botev	kernel density estima..., probability, optimal bandwidth sel..., statistics	148	23	4.22222 4.2 \| 20 ratings

Comments and Ratings Matching Daniel's Watch List			1-5 of 28
Date	File	Comment by	Comments	Rating
08 Jan 2012	kernel density estimation fast and accurate state-of-the-art bivariate kernel density estimator	John	Hi, I just wanted to verify that the volume under the output curve is 1. Right? Thanks	Comment only
09 Dec 2011	kernel density estimation fast and accurate state-of-the-art bivariate kernel density estimator	name	Hi, The 1d version of the kernel estimator also provides cdf values at the representative points. I would like to use these for 2d too. I don't have a strong background on this and I was not able to compute it. Does anyone know how to compute cdf for 2d kernel?	Comment only
29 Nov 2011	kernel density estimation fast and accurate state-of-the-art bivariate kernel density estimator	El-ad David Amir		5
25 Nov 2011	kernel density estimation fast and accurate state-of-the-art bivariate kernel density estimator	Alexander	Hi. For the 1-dimensional estimation you've fixed the "fzero at 293:The function values at the interval endpoints must" error with a try-catch block using : t_star=.28*N^(-2/5); What is the correct expression for kde2d? I'm guessing the power is (-1/3), but what is the coefficient (any where is it coming from)?	5
11 Oct 2011	kernel density estimation fast and accurate state-of-the-art bivariate kernel density estimator	JERRY	I am having the same problem as Gil Tidhar. When using the WAFO kde function, the minimum is 0 (which is what I expected), but your function returns negative values. test code: >> [temp, pab] = kde2d(rand(10000, 2),... >> 2^4, [-3, -3], [5, 5]); >> min(min(pab)) returns -0.0026	Comment only

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