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30 Oct 2009 MOV Physics Movement Author: M P P, M

I can nothing if you don’t understand my programs. Programs are programs. Also I have friends and my friends don’t think this is non-sense. Life is a strange program and this is my Matlab page.
28 Aug 2009 The Four Zero System Circle: the 50.5 business. Author: M P P, M

Hi James,
your reviews take in me always a smile. Funny review.
27 Aug 2009 Physics Color Symmetry Transform physics input in color. Author: M P P, M

max time & space 1-301 & weight 1-1000
---
---
to insert a value of time in [s] with range 0-300: 300
to insert a value of space in [m] with range 0-300: 0
weight value [s^2]: 90000
frequency value [m*s]: 0
wave length value [m]: 0
red value [s]: 0
green value [m]: 0
blue value [m]: 0
velocity value [m/s]: 0.0033
acceleration value [m/s^2]: 1.1111e-005
emotivity value [m^2/s^3]: 3.7037e-008
weight value [s^2]: 0
frequency value [m*s]: 0
wave length value [m]: 0
red value [m]: 0
green value [m]: 300
blue value [m]: 300
velocity value [m/s]: 300
acceleration value [m/s^2]: 300
emotivity value [m^2/s^3]: 90000
---
to insert a value of time in [s] with range 0-300: 300
to insert a value of space in [m] with range 0-300: 1
weight value [s^2]: 90000
frequency value [m*s]: 300
wave length value [m]: 1
red value [s]: 300
green value [m]: 1
blue value [m]: 1
velocity value [m/s]: 0.0033
acceleration value [m/s^2]: 1.1111e-005
emotivity value [m^2/s^3]: 3.7037e-008
weight value [s^2]: 0
frequency value [m*s]: 0
wave length value [m]: 0
red value [m]: 0
green value [m]: 299
blue value [m]: 299
velocity value [m/s]: 299
acceleration value [m/s^2]: 299
emotivity value [m^2/s^3]: 89401
---
---
1 Kg in 1° case --> 1 Kg = 90000 m^2/s^3 and a weight 90000 s^2 ................................ A
1 Kg in 2° case --> 1 Kg = 89401 m^2/s^3 and a weight 90000 s^2 ................................ B
---
1000 Kg in 1° case --> 1000 Kg = 90000 m^2/s^3 and a weight 90000 s^2 .................... C
1000 Kg in 2° case --> 1000 Kg = 89401 m^2/s^3 and a weight 90000 s^2 .................... D
---
---
---
to insert a value of time in [s] with range 0-300: 300
to insert a value of space in [m] with range 0-300: 300
weight value [m/s^2]: 0.0033
frequency value [1/s^2]: 1.1111e-005
wave length value [m]: 300
red value [s=m]: 300
green value [m]: 300
blue value [m]: 300
velocity value [m/s]: 1
acceleration value [m/s^2]: 0.0033
emotivity value [m^2/s^3]: 0.0033
weight value [m/s^2]: 1
frequency value [1/s^2]: 1
wave length value [m]: 0
red value [s=m]: 0
green value [m]: 0
blue value [m]: 0
velocity value [m/s]: 1
acceleration value [m/s^2]: 1
emotivity value [m^2/s^3]: 1
---
1 Kg = 1 m^2/s^3 and a weight 0.0033 m/s^2 .................................. E
1000 Kg = 1 m^2/s^3 and a weight 0.0033 m/s^2 ............................ F
---
---
---
if I stay fine: CDF
in the C case there is max time in a null space (space min) and there is max Kg
in the D case there is max time in an unitary space and there is max Kg
in the F case there is max time in a max space (300 times the unity coinciding with a null space) and there is max Kg
the equal union of space min C and space max F is:
90000 = 1 & 90000 s^2 = 0.0033 m/s^2
90000 = 1 & 90000 s^4 = 0.0033 m
90000 = 1 & 90000*10000 s^4 = 33 m
10000 s^4 = 33 m
to choice C or F is the same, always better then D
priority: C=F and D
---
if I not stay fine: ABE
in the A case there is max time in a null space (space min) and there is min Kg
in the B case there is max time in an unitary space and there is min Kg
in the E case there is max time in a max space (300 times the unity coinciding with a null space) and there is min Kg
the equal union of space min A and space max E is:
90000 = 1 & 90000 s^2 = 0.0033 m/s^2
90000 = 1 & 90000 s^4 = 0.0033 m
90000 = 1 & 90000*10000 s^4 = 33 m
10000 s^4 = 33 m
to choice A or E is the same, always better is B
priority: B and A=E
---
B=D --> 1 = 1000
The equal symbol like union of the better case if I not stay fine and the not better case if I stay fine is a factor: 1:1000.
---
---
---
---
---
more fine
---
Time large
Space little
More weight
---
---
---
less sofference
---
Time little
Space large
Less weight
---
---
---
10000 s^4 = 33 m
---
Space little: more fine
Space large: less sofference
---
---
---
---
---
Space little: more fine --> max = min
---
---
Space min of C case = BLACK
---
frequency value [m*s]: 0
wave length value [m]: 0
red value [s]: 0
green value [m]: 0
blue value [m]: 0
velocity value [m/s]: 0.0033
acceleration value [m/s^2]: 1.1111e-005
emotivity value [m^2/s^3]: 3.7037e-008
---
---
Space max of F case = WHITE
---
frequency value [1/s^2]: 1.1111e-005
wave length value [m]: 300
red value [s=m]: 300
green value [m]: 300
blue value [m]: 300
velocity value [m/s]: 1
acceleration value [m/s^2]: 0.0033
emotivity value [m^2/s^3]: 0.0033
---
---
---
WHITE = BLACK
The white frequency is coinciding with the black acceleration: 1.1111e-005 = 1.1111e-005
The white acceleration is coinciding with the black velocity: 0.0033 = 0.0033
The white emotivity is coinciding with the black velocity: 0.0033 = 0.0033
The white velocity is coinciding with the black frequency: 1 = 0
The white wave length is coinciding with the black wave length: 300 = 0
The white red is coinciding with the black red 300 = 0
The white green is coinciding with the black green 300 = 0
The white blue is coinciding with the black blue 300 = 0
---
---
---
---
---
Space large: less sofference
---
---
Space min of A case = BLACK
---
frequency value [m*s]: 0
wave length value [m]: 0
red value [s]: 0
green value [m]: 0
blue value [m]: 0
velocity value [m/s]: 0.0033
acceleration value [m/s^2]: 1.1111e-005
emotivity value [m^2/s^3]: 3.7037e-008
---
---
Space max of E case = WHITE
---
frequency value [1/s^2]: 1.1111e-005
wave length value [m]: 300
red value [s=m]: 300
green value [m]: 300
blue value [m]: 300
velocity value [m/s]: 1
acceleration value [m/s^2]: 0.0033
emotivity value [m^2/s^3]: 0.0033
---
---
---
WHITE = BLACK
The white frequency is coinciding with the black acceleration: 1.1111e-005 = 1.1111e-005
The white acceleration is coinciding with the black velocity: 0.0033 = 0.0033
The white emotivity is coinciding with the black velocity: 0.0033 = 0.0033
The white velocity is coinciding with the black frequency: 1 = 0
The white wave length is coinciding with the black wave length: 300 = 0
The white red is coinciding with the black red 300 = 0
The white green is coinciding with the black green 300 = 0
The white blue is coinciding with the black blue 300 = 0
---
---
---
---
---
more fine in the BLACK
---
Time large
Space little = min
More weight
---
---
---
less sofference in the BLACK
---
Time little
Space large = min
Less weight
---
---
---
more fine in the WHITE
---
Time large
Space little = max
More weight
---
---
---
less sofference in the WHITE
---
Time little
Space large = max
Less weight
---
---
---
---
---
more fine in the BLACK = less sofference in the BLACK
---
Time large 180° Time little
Space little = Space large --> min = min
More weight 180° Less weight
---
---
---
more fine in the WHITE = less sofference in the WHITE
---
Time large 180° Time little
Space little = Space large --> max = max
More weight 180° Less weight
---
---
---
---
---
Min = Max --> BLACK = WHITE
---
---
more fine in the BLACK = less sofference in the BALCK
---
Time large More weight 360° Time little Less weight
Space little = Space large --> min = min
---
---
more fine in the WHITE = less sofference in the WHITE
---
Time large More weight 360° Time little Less weight
Space little = Space large --> min = min

27 Aug 2009 Physics Color Symmetry Transform physics input in color. Author: M P P, M

Not diagonal system (example)
---
S1 = 10 [s] = input time in MMM --> the watch
M1 = 100 [m] = input space in MMM --> the meter
K2 = 70 [Kg] = input weight in ColorWeight2 --> the balance
---
I’m running 100 meters in 10 seconds.
I write the MMM input.
It say so.
The weight associated to the space time is 100 s^2 because the space number is different to the time number (not diagonal system).
The frequency associated to the space time is 1000 m*s.
The wave length is coinciding with the space (an altitude, a length).
It write 3 color levels.
The red is 100 [m] because I’m not on the diagonal.
The green is 100 [m].
The blue is 100 [m].
It write 3 physics variables.
The velocity is 10 m/s.
The acceleration is 1 m/s^2.
The emotivity is 10 m^2/s^3.
I’ve used only the time altitude dimension, the third dimension, because I’m running on the plane.
I’m running because I’ve a physicity. With a weight.
The balance say 70 Kg.
This data is not used.
However the program has associated physics variables of 3° dimension with my weight.
The weight 100 s^2 is associated to 70 Kg.
The frequency 1000 m*s is associated to 70 Kg.
The wave length, the 100 space meters, is associated to 70 Kg.
The red is associated to 70 Kg.
The green is associated to 70 Kg.
The blue is associated to 70 Kg.
The velocity is associated to 70 Kg.
The acceleration is associated to 70 Kg.
The emotivity is associated to 70 Kg.
Because the 70 Kg are running the 100 meters in 10 seconds.
In the program at this time there is not 70 Kg information.
The obtained results has certainly an union with the 70 Kg but the output numbers are without 70 Kg dependence because I haven’t used this weight quantity.
Now is the moment to use also the weight value.
The ColorWeight2 take in input time space and weight.
Is necessary to insert a red quantity.
From MMM computation I’ve the red quantity. This number is obtained with MMM logic and it is the same logic of ColorWeight2.
Start program.
The seconds and the meters live in a range 30100 values.
They’ve a correlation with green and blue color. And I’ve this number from MMM, like the red.
I wirte the data input with this logic: to obtain the same time altitude green blue of MMM.
to select a row of time in seconds (1-30100): 10010
to select a column of space in meters (1-30100): 10100
Now the computer want the red color.
to select the red color (0-300): 100
I write the MMM red and so there is union with the weight of 70 Kg.
Are obtained output.
red profundity = 100
green profundity = 100
blue profundity = 100
[s] = 10
[m] = 100
[m/s] = 10
[m/s2] = 1
There is two programs coincidence.
There is also this.
[kg] = 1
[kg*m/s2] = 1
The 70 Kg data is not on the machine, like in MMM. And there is also now weight information. It is obtained thanks to the acceleration formula. The weight obtained is an inverse acceleration. In this way the weight force, like weight per acceleration, is always unitary.
The union with the equal symbol of the MMM weight with this weight is: 100 s^2 = 1 Kg = 1 s^2/m
The result is: altitude = 1/100 [m].
And so: 100 m = 1/100 m --> 10000 m = 1 m --> 10 Km = 1m
The 100 meters are 1/100 of meter if 1 Kg is coinciding with 100 s^2.
Is obtained the MMM-ColorWeight2 union.
The 100 meters are 1 cm because 1 Kg is coinciding with 100 s^2 if the double RGB is the same.
And the double RGB is the same because the two systems has the same quantity numbers.
To run 100 meters with a weight of 100 s^2 is equal to run 1 cm with a kilogram.
The 70 Kg aren’t used at this time.
The weight range is from 1 to 1000.
My weight could be 1 Kg or 123 Kg or 999 Kg: the same result.
The data are indipendent to the weight.
Comparison.
A man with a weight of 210 Kg is running the 100 meters in 10 seconds. At this program time the results are the same quantities: the same time and the same space. But my weight is 70 Kg and the man weight is 210 Kg. The same results with a difference in the energy production. The same numbers in the third dimension because the color output is the same but a different energy quantity because the spacetime is the same and the weight is not the same.
To run 100 meters with a weight of 100 s^2 is equal to run 1 cm with a kilogram, for me and also for the man and also for the other all weight quantities.
---
I write 70 Kg in input.
to insert a positive number of weight [Kg] with range 1-1000: 70
Is obtained this.
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN
velocity [m/s] axes: T / Y 10
gravity [m/s^2] axes: T / Y^2 1
altitude / time^2 [m/s^2] axes: T / Y^2 1
gravity / velocity [1/s] axes: 1 / T 0.1000
velocity / gravity [s] axes: Y 10
mass [s^2/m] axes: Y^2 / T 1
1 / velocity [s/m] axes: Y / T 0.1000
1 / gravity [s^2/m] axes: Y^2 / T 1
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.1429
weight / time [Kg/s] axes: XZ / Y 7
time / weight [s/Kg] axes: Y / XZ 0.1429
weight / mass [Kg*m/s^2] axes: XZT / Y^2 70
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 70
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN + 100
velocity [m/s] axes: T / Y 0.9091
gravity [m/s^2] axes: T / Y^2 0.0083
altitude / time^2 [m/s^2] axes: T / Y^2 0.0083
gravity / velocity [1/s] axes: 1 / T 0.0091
velocity / gravity [s] axes: Y 110
mass [s^2/m] axes: Y^2 / T 121
1 / velocity [s/m] axes: Y / T 1.1000
1 / gravity [s^2/m] axes: Y^2 / T 121
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0130
weight / time [Kg/s] axes: XZ / Y 0.6364
time / weight [s/Kg] axes: Y / XZ 1.5714
weight / mass [Kg*m/s^2] axes: XZT / Y^2 0.5785
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 8470
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN + 200
velocity [m/s] axes: T / Y 0.4762
gravity [m/s^2] axes: T / Y^2 0.0023
altitude / time^2 [m/s^2] axes: T / Y^2 0.0023
gravity / velocity [1/s] axes: 1 / T 0.0048
velocity / gravity [s] axes: Y 210
mass [s^2/m] axes: Y^2 / T 441
1 / velocity [s/m] axes: Y / T 2.1000
1 / gravity [s^2/m] axes: Y^2 / T 441
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0068
weight / time [Kg/s] axes: XZ / Y 0.3333
time / weight [s/Kg] axes: Y / XZ 3
weight / mass [Kg*m/s^2] axes: XZT / Y^2 0.1587
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 30870
point of half: clock verse dynamic solution without weight
time = -60
space = 30
velocity = -60
acceleration = -69
mass = -69
weight force = -69
clock verse dynamic solution = perception of the color weight
---
Now I write the 210 Kg data.
to insert a positive number of weight [Kg] with range 1-1000: 210
Is obtained this.
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN
velocity [m/s] axes: T / Y 10
gravity [m/s^2] axes: T / Y^2 1
altitude / time^2 [m/s^2] axes: T / Y^2 1
gravity / velocity [1/s] axes: 1 / T 0.1000
velocity / gravity [s] axes: Y 10
mass [s^2/m] axes: Y^2 / T 1
1 / velocity [s/m] axes: Y / T 0.1000
1 / gravity [s^2/m] axes: Y^2 / T 1
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0476
weight / time [Kg/s] axes: XZ / Y 21
time / weight [s/Kg] axes: Y / XZ 0.0476
weight / mass [Kg*m/s^2] axes: XZT / Y^2 210
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 210
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN + 100
velocity [m/s] axes: T / Y 0.9091
gravity [m/s^2] axes: T / Y^2 0.0083
altitude / time^2 [m/s^2] axes: T / Y^2 0.0083
gravity / velocity [1/s] axes: 1 / T 0.0091
velocity / gravity [s] axes: Y 110
mass [s^2/m] axes: Y^2 / T 121
1 / velocity [s/m] axes: Y / T 1.1000
1 / gravity [s^2/m] axes: Y^2 / T 121
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0043
weight / time [Kg/s] axes: XZ / Y 1.9091
time / weight [s/Kg] axes: Y / XZ 0.5238
weight / mass [Kg*m/s^2] axes: XZT / Y^2 1.7355
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 25410
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN + 200
velocity [m/s] axes: T / Y 0.4762
gravity [m/s^2] axes: T / Y^2 0.0023
altitude / time^2 [m/s^2] axes: T / Y^2 0.0023
gravity / velocity [1/s] axes: 1 / T 0.0048
velocity / gravity [s] axes: Y 210
mass [s^2/m] axes: Y^2 / T 441
1 / velocity [s/m] axes: Y / T 2.1000
1 / gravity [s^2/m] axes: Y^2 / T 441
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0023
weight / time [Kg/s] axes: XZ / Y 1
time / weight [s/Kg] axes: Y / XZ 1
weight / mass [Kg*m/s^2] axes: XZT / Y^2 0.4762
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 92610
point of half: clock verse dynamic solution without weight
time = -200
space = -110
velocity = -200
acceleration = -209
mass = -209
weight force = -209
clock verse dynamic solution = perception of the color weight
---
Comparison.
The same results.
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN
velocity [m/s] axes: T / Y 10
gravity [m/s^2] axes: T / Y^2 1
altitude / time^2 [m/s^2] axes: T / Y^2 1
gravity / velocity [1/s] axes: 1 / T 0.1000
velocity / gravity [s] axes: Y 10
mass [s^2/m] axes: Y^2 / T 1
1 / velocity [s/m] axes: Y / T 0.1000
1 / gravity [s^2/m] axes: Y^2 / T 1
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0476
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN + 100
velocity [m/s] axes: T / Y 0.9091
gravity [m/s^2] axes: T / Y^2 0.0083
altitude / time^2 [m/s^2] axes: T / Y^2 0.0083
gravity / velocity [1/s] axes: 1 / T 0.0091
velocity / gravity [s] axes: Y 110
mass [s^2/m] axes: Y^2 / T 121
1 / velocity [s/m] axes: Y / T 1.1000
1 / gravity [s^2/m] axes: Y^2 / T 121
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN + 200
velocity [m/s] axes: T / Y 0.4762
gravity [m/s^2] axes: T / Y^2 0.0023
altitude / time^2 [m/s^2] axes: T / Y^2 0.0023
gravity / velocity [1/s] axes: 1 / T 0.0048
velocity / gravity [s] axes: Y 210
mass [s^2/m] axes: Y^2 / T 441
1 / velocity [s/m] axes: Y / T 2.1000
1 / gravity [s^2/m] axes: Y^2 / T 441
---
Comparison.
Not the same results.
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN
With 70.
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.1429
weight / time [Kg/s] axes: XZ / Y 7
time / weight [s/Kg] axes: Y / XZ 0.1429
weight / mass [Kg*m/s^2] axes: XZT / Y^2 70
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 70
With 210.
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0476
weight / time [Kg/s] axes: XZ / Y 21
time / weight [s/Kg] axes: Y / XZ 0.0476
weight / mass [Kg*m/s^2] axes: XZT / Y^2 210
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 210
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN + 100
With 70.
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0130
weight / time [Kg/s] axes: XZ / Y 0.6364
time / weight [s/Kg] axes: Y / XZ 1.5714
weight / mass [Kg*m/s^2] axes: XZT / Y^2 0.5785
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 8470
With 210.
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0043
weight / time [Kg/s] axes: XZ / Y 1.9091
time / weight [s/Kg] axes: Y / XZ 0.5238
weight / mass [Kg*m/s^2] axes: XZT / Y^2 1.7355
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 25410
PHYSICS CORRELATIONS of the weight inserted in ZERO UP and ZERO DOWN + 200
With 70.
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0068
weight / time [Kg/s] axes: XZ / Y 0.3333
time / weight [s/Kg] axes: Y / XZ 3
weight / mass [Kg*m/s^2] axes: XZT / Y^2 0.1587
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 30870
With 210.
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 0.0023
weight / time [Kg/s] axes: XZ / Y 1
time / weight [s/Kg] axes: Y / XZ 1
weight / mass [Kg*m/s^2] axes: XZT / Y^2 0.4762
mass / weight [s^2/(Kg*m)] axes: Y^2 / XZT 92610
With 70.
point of half: clock verse dynamic solution without weight
clock verse dynamic solution = perception of the color weight
time = -60
space = 30
velocity = -60
acceleration = -69
mass = -69
weight force = -69
With 210.
point of half: clock verse dynamic solution without weight
clock verse dynamic solution = perception of the color weight
time = -200
space = -110
velocity = -200
acceleration = -209
mass = -209
weight force = -209
---
Conclusion.
The 1° triple color (R=G=B=100) system is an emotivity 10 m^2/s^3 with a weight 70 Kg: 70 Kg = 10 m^2/s^3.
The 2° triple color (R=G=B=100) system is an emotivity 10 m^2/s^3 with a weight 210 Kg: 210 Kg = 10 m^2/s^3.
The proportional unitive factor is 3.
The same emotive quantity of 3° dimension is a weight 3 times bigger in the 2° case.
The same color solution is a weight 3 times bigger in the 2° case.
Better or not better?
In the 2° case the production is 3 times the 1° case production. Like production is a better way the second. But like consume is a better way the first case. With 210 Kg the energy is a production 3 times superior but at the same time is a consume 3 times superior.
Limit case. An infinitesimal weight and an infinite weight with the same 3° dimension quantities: the same movement, a coincident dynamicity. The infinitesimal case is a minimum energy consume, the infinite case is a maximum energy consume and the proportional unitive factor is an infinite square.
With a neuro-current association the double system is only one system: the infinitesimal case (70 Kg) is right down point of current and the infinite case (210 Kg) is right up point of current and the infinite square proportional unitive factor (the 3) is left point of current, central reference like bidimensional plane. The reference plane and the choose of the right down or the reference plane and the choose of the right up. In a case is a soft emotivity (and it is fine if I not stay fine and it is not fine if I stay fine) and in the other case is a strong emotivity (and it is not fine if I not stay fine and it is fine if I stay fine).

27 Aug 2009 Physics Color Symmetry Transform physics input in color. Author: M P P, M

Input Output: scheme MMM-ColorWeight2
---
Input MMM = (S1,M1) --> K1 R1 G1 B1
Input ColorWeight2 = (S2,M2,R2,K2) --> S3 M3 K3 R2 G2 B2
---
time: S1 s = S2 s
space: M1 m = M2 m
weight on the diagonal: K1 m/s^2 = R2 = K2 Kg
weight not diagonal: K1 s^2 = R2 = K2 Kg
red: R1 = R2 = K3 Kg
green: G1 = G2 = S3 s
blue: B1 = B2 = M3 m
---
K1 m/s^2 = K3 Kg --> weight on the diagonal = red
K1 s^2 = K3 Kg --> weight not diagonal = red
K2 Kg = R1 --> weight = red
R2 = R2
S1 = S3
M1 = M3
S2 = G2 = G1
M2 = B2 = B1
---
---
condition Input Output: R2 = R1
---
Input MMM = (S1,M1) --> K1 R1 G1 B1
Input ColorWeight2 = (S2,M2,R1,K2) --> S3 M3 K3 R1 G2 B2
---
time: S1 s = S2 s
space: M1 m = M2 m
weight on the diagonal: K1 m/s^2 = R1 = K2 Kg
weight not diagonal: K1 s^2 = R1 = K2 Kg
red: R1 = R1 = K3 Kg
green: G1 = G2 = S3 s
blue: B1 = B2 = M3 m
---
K1 m/s^2 = K3 Kg --> weight on the diagonal = red
K1 s^2 = K3 Kg --> weight not diagonal = red
K2 Kg = R1 --> weight = red
R1 = R1
S1 = S3
M1 = M3
S2 = G2 = G1
M2 = B2 = B1
---
input: 5+1
output: 8+1
---
---
condition Input Output: R2 = R1 & S2=S3G2 & M2=M3B2
---
Input MMM = (S1,M1) --> K1 R1 G1 B1
Input ColorWeight2 = (S2,M2,R1,K2) --> K3 R1 S2 M2
---
time: S1 s = S2 s
space: M1 m = M2 m
weight on the diagonal: K1 m/s^2 = R1 = K2 Kg
weight not diagonal: K1 s^2 = R1 = K2 Kg
red: R1 = R1 = K3 Kg
green: G1 --> S2
blue: B1 --> M2
---
K1 m/s^2 = K3 Kg --> weight on the diagonal = red
K1 s^2 = K3 Kg --> weight not diagonal = red
K2 Kg = R1 --> weight = red
R1 = R1
S1 --> S2 = G1
M1 --> M2 = B1
---
input: 5+1
output: 6+1
---
---
5 input
S1 = the time in MMM
M1 = the space in MMM
S2 = the time in ColorWeight2 with range 30100
M2 = the space in ColorWeight2 with range 30100
K2 = the weight in ColorWeight2
---
one
R1 = the red in output in MMM
R2 = the red in input in ColorWeight2
---
6 output
K1 = the weight in MMM
G1 = the green in MMM
B1 = the blue in MMM
S3 = the time in ColorWeight with range 100
M3 = the space in ColorWeight2 with range 100
K3 = the weight in ColorWeight2
---
2 output
S2 = the time in ColorWeight2 with range 30100
M2 = the space in ColorWeight2 with range 30100
---
two
G2 = the green in output in ColorWeight2
B2 = the blue in output in ColorWeight2
---
2 output & two --> 2 output
S3 = S2 & G2
M3 = M2 & B2
---
2 output & two --> 2 input
S2 = S3 & G2
M2 = M3 & B2
---
2 input = 2 output
S2 = S3
M2 = M3
---
8 output
K1 = the weight in MMM
G1 = the green in MMM
B1 = the blue in MMM
S3 = the time in ColorWeight with range 100
M3 = the space in ColorWeight2 with range 100
K3 = the weight in ColorWeight2
S2 = the time in ColorWeight2 with range 30100
M2 = the space in ColorWeight2 with range 30100
---
8 output
K1 = the weight in MMM
G1 = the green in MMM
B1 = the blue in MMM
S3 = the time in ColorWeight with range 100
M3 = the space in ColorWeight2 with range 100
K3 = the weight in ColorWeight2
G2 = the green in output in ColorWeight2
B2 = the blue in output in ColorWeight2
---
10 output
K1 = the weight in MMM
G1 = the green in MMM
B1 = the blue in MMM
S3 = the time in ColorWeight with range 100
M3 = the space in ColorWeight2 with range 100
K3 = the weight in ColorWeight2
S2 = the time in ColorWeight2 with range 30100
M2 = the space in ColorWeight2 with range 30100
G2 = the green in output in ColorWeight2
B2 = the blue in output in ColorWeight2
---
4 output
K1 = the weight in MMM
G1 = the green in MMM
B1 = the blue in MMM
K3 = the weight in ColorWeight2
---
six
S3 = the time in ColorWeight with range 100
M3 = the space in ColorWeight2 with range 100
S2 = the time in ColorWeight2 with range 30100
M2 = the space in ColorWeight2 with range 30100
G2 = the green in output in ColorWeight2
B2 = the blue in output in ColorWeight2
---
3 input
S1 = the time in MMM
M1 = the space in MMM
K2 = the weight in ColorWeight2
---
3 input --> six
S1 = the time in MMM --> S2 S3
M1 = the space in MMM --> M2 M3
K2 = the weight in ColorWeight2 --> G2 B2
---
4 output
K1 = the weight in MMM
G1 = the green in MMM
B1 = the blue in MMM
K3 = the weight in ColorWeight2
---
1 output --> 2 input
K1 = the weight in MMM --> S1 M1
---
1 input --> 3 output
K2 = the weight in ColorWeight2 --> G1 B1 K3
---
1 output = 1 input
K1 = K2
the weight in MMM = the weight in ColorWeight2
---
2 input = 3 output
S1 M1 = G1 B1 K3

21 Aug 2009 MATLAB rooms KMN Color simulation of the neural instants physicity. Author: M P P, M

Then POC, profundity is color profundity.
20 Aug 2009 isodd: a pedestrian parity checker ISODD returns TRUE for integers of any numeric MATLAB class that are not evenly divisible by 2 Author: us P, M

Maybe you are the Herbert West re-animator of Brian Yuzna masterpieces. I hope is so! :))
20 Aug 2009 ColorWeight (double version) The color weight without weight. Author: M P P, M

m=ms
m=Kg2
ms=Kg2
---
ms=Kg --> TY=Z2/X
---
Kg2=Kg --> Kg=1 --> Z2=X
Z=sqrt(10)
X=10
---
20.6809 circles of 0.0044 time = 0.091 time --> 360° = circle = matrix 100x100 --> 2500 = 90°
the number of two system union appear to be 200 --> 2500/12.5 = 200 --> 90°/12.5=7.2°
200 = 7.2° --> number of two system union
60 sec = 360° --> 1 min = circle --> 1 sec = 6°
60 min = 360° --> 1 hour = circle --> 1 min = 6°
60 sec = 1 min --> 360° = 6° --> factor = 60
60 min = 1 hour --> 360° = 6° --> factor = 60
factor^2 = 3600 --> number of sec in one hour
200 = factor^2/18 --> number of sec in 1/18 of hour
7.2° = factor^2/18 --> number of sec in 1/18 of hour
360°/7.2° = 50 --> 1 hour / 50 = 7.2° with 1 hour = 360°
360°/7.2° = 50 --> 1 min / 50 = 7.2° with 1 min = 360°
factor --> 1 min = 1 hour
factor^2 --> 1 min * 1 min = 1 hour * 1 hour
3600 --> 360° * 360° = 360° * 360°
factor^2 = 3600 --> 1 min square = 360° square --> number of sec in one hour --> 3600 sec = 129600°
factor^2 = 3600 --> 1 hour square = 360° square --> number of sec in one hour --> 3600 min = 129600°
129600/7.2=18000
18000° * number of two system union = 129600° --> way sec and way min
129600/200=648
648 * number of two system union = 129600° --> way sec and way min
18° = 0.648 --> 129.6° = 129.6° --> way sec / 1000 and way min / 1000
9° = 0.324 --> 64.8° = 64.8° --> way sec / 2000 and way min / 2000
---
212+112=324 --> velocity/gravity in 3° level more the velocity/gravity in 2° level with 2° and 3° level in one hundred union and define this value VG --> 9000° = VG --> 18000° = 2 * VG
2 * VG * number of two system union = 129600° --> way sec and way min
VG * number of two system union = 64800° --> way sec / (2*VG) and way min / (2*VG)
number of two system union = 64800° / VG --> way sec / (2*VG) and way min / (2*VG)
number of two system union = 7.2 --> way sec / 18000° and way min / 18000°
---
I write in the program the solution of identity: (1,26018,0,1).
Physics point
red space [m] = 18
green space [m] = 18
red acceleration [m/s2] = 18
green acceleration [m/s2] = 18
clock verse dynamic solution
[m] = 18
[m/s] = 18
[m/s2] = 18
static solution: instant sector n° 1
acceleration [m/s2] = 18
physics correlations
altitude / time [m/s] axes: T / Y 18
time / weight [s/Kg] axes: XY / Z^2 18
VFA = velocity * force * acceleration = altitude / ( time * weight^2 ) = 18
altitude / weight [m/Kg] axes: T / XZ 18
altitude * weight / time [m*Kg/s] axes: XZT / Y 18
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 18
gravity [m/s^2] axes: T / Y^2 18
altitude / time^2 [m/s^2] axes: T / Y^2 18
weight / mass [Kg*m/s^2] axes: XZT / Y^2 18
altitude / ( time * weight ) [m/(s*Kg)] axes: T / XZY 18
altitude / weight [m/Kg] axes: XT / Z^2 324
altitude * time / weight [m*s/Kg] axes: XTY / Z^2 324
---
18° = 2*VG/1000
---
m=° --> red space = green space = 2*VG/1000
m=° & s2=1 --> red acceleration = green acceleration = 2*VG/1000
m=° & s=1 --> altitude / time = 2*VG/1000
s=° & Kg=1 --> time / weight = 2*VG/1000
m=° & Kg=1 --> altitude / weight = 2*VG/1000
m=° & Kg=s --> altitude * weight / time = 2*VG/1000
m=° & Kg=1/s --> altitude / ( time * weight ) = 2*VG/1000
m=° & s^2=1 --> gravity = altitude / time^2 = 2*VG/1000
m=° & Kg=s^2 --> weight / mass = 2*VG/1000
---
18° = 0.648 --> 129.6° = 129.6° --> way sec / 1000 and way min / 1000
---
2*VG/1000 = 0.648 --> VG = 648/2 = 324
9000° = 324 --> number of two system union
9000/324=27.7778
200/7.2=27.7778
Two systems union is VG value and it is in Y dimension: 605.0728 = time of union of the two equal solutions.
9000° = 324 --> 605.0728
324*1.8675=605.0728
9000°*1.8675=16808°
605.0728 = 16808° --> time of union = time of union --> 1 = 27.7778°
---
90° : 15 sec=min = 27.7778° : X sec=min --> X = 4.6296 [sec=min] --> time of union
4.6296 sec --> speed up
4.6296 min --> speed down
speed up = speed down --> factor = 60
The double speed way is the present instant like diagonal of 60 elements in a matrix of 60 rows (speed up, sec) per 60 column (speed down, min).
60 = 60 --> factor^2 = 3600
The equal speed of the two ways is the speed^2 definition like number of seconds in one hour and this is 60 circles with circle equal minute.
With a current association I say this:
right point of current up = 60 = PDX/2
right point of current down = 60 = PDX/2
PDX^2/4=3600=PSX --> the perceptive plane 2D, the speed^2 definition like 60 circles with circle equal minute, the left point of current.
Current=PSX+PDX=3720
---
Are we the same opinion? Say to me, regards.

20 Aug 2009 MATLAB rooms KMN Color simulation of the neural instants physicity. Author: M P P, M

Because this is the better place. In my purposes I intend to say with precision my idea and the results are arriving, this is what appear to my eyes. I’m here to work with passion and to speack with other authors and to say their programs. Is or is not the File Exchange function this? I know my simple programming style and I have big esteem of the sophisticated other styles but also think to have something to show. With umility, in peace. Of scientific value in my productions there is the computation like the others productions. In my mind all is a scientific value, all is very important, the difficult thing is to put in order the big number of combinations but all has an importance. The us review is been a fantastic dream, I’m not crazy, I know that super researchers (and their laboratories) have in their minds years and years of experience and this is an incentive to work fine and this is love for the science. In conclusion I have also to say that my files theory is strange, I know this, but I’m sure. Not a morning day for a theory but years of research, with reliability. I'm not here to say lies, for what?! A function program is always something. if no I'm a madman :) out of order am I? NO! :))) Regards
20 Aug 2009 ColorWeight (double version) The color weight without weight. Author: M P P, M

Matt say
Color is motion in detection of point reference metric.
Read this
Color is motion in the video profundity dimension and this is the XZ weight.
Color is motion in detection of point reference metric second.
Video profundity dimension is a metric second weight reference.
weight / ( time * altitude ) = 1 --> weight = time * altitude
Video profundity dimension is a weight^2 reference.
Color is motion in the weight^2 reference.
Color is motion in detection of point reference Kg square.
Union of the Matt words with this statements: [m=Kg^2]
Axial: T = Z^4/X^2 --> Kg in Z^2/X
T = future time
Z = video altitude
X = video width
---
Y = past time
T / Y = t = present instant
T = Y^2 --> t = Y
T = Z^3 --> X^2 = Z
Y = Z^3 --> T = Y --> t = 1
Y = Y^2 --> Z^3 = T --> 1 = Y
---
XT/Z^2 = Z^2/X --> m/Kg=Kg
1/Kg = Kg --> m=1
T = 1 --> X/Z^2=Z^2/X --> X^2=Z^4
In a spacetime matrix 100x100 this is:
X=10 --> X^2=100
Z=sqrt(10) --> Z^2 = 10
Z^2=10 --> Z^4 = 100
It is T=1.
100 = 100 --> X^2 = Z^4
T = 1 --> Z^3=1 --> Z^2 = 1/Z --> sqrt(10) = 1/10 --> 10 = 1/100 --> 1 = 1000
1 = 1000 --> 1 = Z^6 --> 1 = T * Y --> 1 = X^12
1 = a cube 10x10x10 --> 1 = Z^6 = TY = X^12
5:1000 --> one value of difference each 200 values
1*1*1 = 1000^3 --> 1 = Z^18 = (TY)^3 = X^36
5^3:1000^3=125:1000000000 --> one value of difference each 200^3=8000000 values
2D --> one value of difference each 200^2=40000 values
2D --> one value of difference each spacetime matrix 100x100 per 4 times
In the two systems there is one value of difference each 200 values: 40000/200=200
200 values of two systems difference * 200 times is one value of difference and it is 40000 values
50 elements each 10000 * 200 times are 40000 elements and this is the spacetime matrix 100x100 per 4 times
one value of difference is the spacetime matrix 100x100 per 4 times if each value is a matrix element
I think this: the two systems difference is the spacetime matrix 100x100 per 4 times each 200 values because one value of difference is the spacetime matrix 100x100 per 4 times. In formula I say this:
the difference value quarter = spacetime matrix 100x100
the difference value quarter each 50 values = spacetime matrix 100x100 each 50 values
In the previous comment I wrote: our difference is 50 elements of the 100x100 matrix.
I can write now: our difference is the different value quarter of the 100x100 matrix.
Our difference is the different value of a matrix with 2500 elements.
What is the meaning of this statement? In my program 2500 elements are a quarter of spacetime reference.
A different value of our spacetime quarter: 50 elements of difference in 10000 are 12.5 elements in 2500 and 12.5*200 is 2500. The number of two system union appear to be 200.
I write in the program the start solution: (12,12,12,12).
The weight inserted in ZERO UP and ZERO DOWN + 100 say this:
velocity / gravity [s] axes: Y 112
The weight inserted in ZERO UP and ZERO DOWN + 200 say this:
velocity / gravity [s] axes: Y 212
The utility is this: 2*(212-112)=200
The number of two system union is 2 times the velocity/gravity in 3° level less the velocity/gravity in 2° level with 2° and 3° level in one hundred union. The one hundred union is situation of the altitude dimension (T axes of future time). Two times this situation is the number of two system union in T axiality). The 100+100 is the systems union and 100 (the one hundred situation) is half union of the double system in T because 212 in Y less 112 in Y is a complete union in Y:
half double system union in T = 100 in Y --> 100 double system in T = 100 in Y
double system in the present instant = 1
Yes, I say; my system in the present instant is 0.5 and your system in the present instant is 0.5 and so the present instant is a double model unity.

20 Aug 2009 ColorWeight (double version) The color weight without weight. Author: M P P, M

for the same X space like 0 = 0 are necessary 20.6809 circles of zero time
zero time = 0.0044 time
for the same X space like 0 = 0 are necessary 20.6809 circles of 0.0044 time
20.6809 circles of 0.0044 time = 0.091 time
for the same X space like 0 = 0 is necessary a 0.091 time
0.22 / 0.091 = 2.4176
1463 = 18000° --> time 0.22 --> 1463 = 50 circles --> 2.4176 * time 0.091
our systems has: velocity = weight force = -11 = -50 * 2.4176 * 0.091
-11 = -50 * 2.4176 * 0.091 --> -11 = -11.0001 --> 1/10000 = element of a 100^2 matrix
0.0001*50=0.005 --> our difference
my conclusion is this: our difference is 50 elements of the 100x100 matrix
our difference --> 10x5 matrix --> space = 2 time or time = 2 space --> 0 = 2 * 0
each 100 values of X or Z there is an element of difference --> zero
each 200 values of Z or X there is an element of difference --> 2 * zero
5:1000 --> one value of difference each 200 values
1000 = 10^3 = a cube 10x10x10 = 5x5x5x2x2x2 = 5x10x20
5:1000 --> 5:5x10x20
10 --> zero/10
20 --> zero/5
Our difference is a confirmation of equal solutions, both ok.
Is this resolving?

20 Aug 2009 ColorWeight (double version) The color weight without weight. Author: M P P, M

0 = space
0 = time
0 = 67 --> difference in the space
0^2 = 856 --> difference in the time^2
0/0^2 = 0.0783 = number of acceleration difference in the two solutions
0.0783 = 0 in a time of 605.0728 is 0/0^2 = 0 in X/Z^2
0 = 0 --> 0^2 = null --> 0 = sqrt(null) --> this is a zero time --> 856 = null
sqrt(856) = 29.2575
zero time --> 0 = 29.2575
---
0.0783 = 0 in a time of 605.0728 is 0 = 0 in X and this is the X = 0
0^2 in Z^2 is null in Z^2
0 in Z is sqrt(null) in Z --> the zero time: 0 in Z is 29.2575 in Z
---
X = 0 is 0
Z = 0 is 29.2575
the zero time is the XZ union: X=Z is 0=0 and it is 0=29.2575
---
605.0728 /29.2575 = 20.6809 = number of zero time ripetition to have a time of 605.0728
20.6809 ripetitions of 29.2575 are a time of 605.0728 --> 0 = 0 in X --> 0.0783 = 0
---
0.0783-0.0043 = 0.0740 --> 0.0783 = 0 in a time of 605.0728
0.0783-0.0043 = 0.0740 --> 0.0783 = 0 with 20.6809 ripetitions of 29.2575
0.0783-0.0043 = 0.0740 --> 0.0783 = 0 with 20.6809 ripetitions of Z = 0
---
0 = 0 in X is Z = Z in X --> 0.0783 = 0 --> a time of 605.0728
---
with 20.6809 circles of zero time we obtain 0 = 0 in X and this is the 0^2 = null
0.0783-0.0043 = 0.0740 --> 0/0^2 = 0 in X/Z^2
---
-11.9167 = -11.921 --> 0.0043 = 0 in a time of 605.0728
-11.9167 = -11.921 --> 0.0043 = 0 with 20.6809 ripetitions of 29.2575
-11.9167 = -11.921 --> 0.0043 = 0 with 20.6809 ripetitions of Z = 0
---
0.0783-0.0740 = 0.0043 --> 0/0^2 = 0 in X/Z^2
0.0043 = 0.0043 --> 20.6809 circles of zero time are 0 = 0 in X --> 0^2 = null
for the same X space like 0 = 0 are necessary 20.6809 circles of zero time
29.2575 = 360° --> the zero time
20.6809 circles of zero time are the equal solutions
20.6809 ripetitions of Z = 0 are the equal solutions
a time of 605.0728 is an union time of two different solutions and it is the time of separation of two equals solutions
---
605.0728 / 60 = 10.0845 = number of minutes to obtain a time of 605.0728 [s]
0.0845 min = 0.0845 * 60 sec = 5.07 sec = 5 sec + 7/100 of sec
10 min + 5 sec + 7/100 of sec --> 0 = 0 in X --> 0.0783 = 0
---
0.0043 [m/s^2] * 605.0728 [s] = 2.6018 [m/s] = number of velocity for the same solution
0.0043 [m/s^2] * ( 10 min + 5 sec + 7/100 of sec ) = 2.6018 [m/s]
2.6018 [m/s] like diagonal of the spacetime matrix 2D
I write this input in ColorWeight2:
to select a row of time in seconds (1-30100): 1
to select a column of space in meters (1-30100): 26018 --> the same solution * 10000
to select the red color (0-300): 0 --> black in the first color level, we are in the same solution
to insert a positive number of weight [Kg] with range 1-1000: 1 --> seconds = Kg
Result:
red profundity = 0 --> 2D of space
green profundity = 0 --> time forward
blue profundity = 260 --> time behind <-
PHYSICS POINT
red time [s] = 2
green time [s] = 2
blue time [s] = -0.7333
red space [m] = 18
green space [m] = 18
blue space [m] = 2.4000
red velocity [m/s] = 9
green velocity [m/s] = 9
blue velocity [m/s] = 1.2000 <- (*)
red acceleration [m/s2] = 18
green acceleration [m/s2] = 18
blue acceleration [m/s2] = 2.4000 <- (*) (X)
red mass [kg] = 0.0556
green mass [kg] = 0.0556
blue mass [kg] = 0.0074 <- (X)
red weight force [kg*m/s2] = 1
green weight force [kg*m/s2] = 1
blue weight force [kg*m/s2] = 0.1333 <- (X)
clock verse dynamic solution: point of half with weight in 301 static sectors instant
[s] = 1
[m] = 18
[m/s] = 18 <- (**)
[m/s2] = 18 <- (**)
[kg] = 0.0556 <- (****)
[kg*m/s2] = 1 <- (*****)
zero up = 18
zero down = 1
point of half: clock verse dynamic solution without weight
time = 0
space = 17
velocity = 17 <- (***)
acceleration = 17 <- (***)
mass = -0.9444 <- (****)
weight force = 0 <- (*****)
---
(*) --> velocity = acceleration/2 --> time = 0.5 in the physics point
(**) --> time = 1
(***) --> time = 1
clock verse dynamic solution = point of half --> time = time
(****) --> clock verse dynamic solution + point of half --> 2 * time --> 0.0556 - 0.9444 = 2 * mass = -0.8888
(*****) --> 0 = 1
2 * time = 2 * 0.5 = 1 = double time in the physics point --> 2 * mass = -0.8888 --> mass = -0.4444
[s=Kg] --> double time in the physics point = -0.4444 --> physics point time = -0.2222 = half physics point
(X) --> blue mass * blue acceleration = blue weight force --> 0.0178 = 0.1333 --> 0.1155 of difference
if 0.0044 of difference is zero then a double difference is 0.2222 and it is 50.5 times the zero
---
10000 times the same solution is 26018 [m] like horizontal of the space line 1D and it is 50.5 times the zero
the same solution is 2.6018 [m] like horizontal of the space line 1D and it is 50.5/10000 times the zero
0.005 times the zero=0.0044 is a not difference because the definition of the zero value is the not different solution
29.2575 = 360° --> the zero time --> the 0.0044 time
0.005 * 29.2575 = 0.005 * 360° --> 0.005 times the 0.0044 time --> 0.1463 = 1.8° --> time 2.2e-5
1463 = 18000° --> time 0.22 --> 1463 = 50 circles
---
our systems has: velocity = weight force = -11 = -50 * 0.22
What do you think of this solution?
Can I ask how many input has your system?

19 Aug 2009 MATLAB rooms KMN Color simulation of the neural instants physicity. Author: M P P, M

oh oh, thank you us, this is a news :)))
19 Aug 2009 ColorWeight (double version) The color weight without weight. Author: M P P, M

acceleration = -11.9167
acceleration = NN/N^2-W= (1/12)-12 = (0.0833)-12 = (12/144)-12
N = 12 --> time Z
NN = 12 --> space X
W = 12 --> XZ, the video plane
---
acceleration = -11.921
acceleration = (0.0790)-12 = (79/1000)-12
---
X --> 12 = 79 --> 67 of difference in the space
Z^2 --> 144 = 1000 --> 856 of difference in the time^2
X/Z^2 --> 67/856 = 0.0783 = number of acceleration difference in the two solutions
---
X/(12*Z) --> 1/12 in my result, this is a velocity/12
X/(12*Z) --> 79/(12*sqrt(1000)) in your result, this is a velocity/12
1/12 = 79/(12*sqrt(1000)) --> 79 = sqrt(1000) --> 47.3772 = number of velocity difference in the two solutions
---
my velocity = your velocity = -11
my time = your time = 0
---
47.3772 = 0 * 0.0783 --> vel diff / time = acc diff --> 0 = 605.0728 = time of union of the two equal solutions
---
-11.9167 = -11.921 --> 0.0043 = 0 in a time of 605.0728
---
0.0043 [m/s^2] * 605.0728 [s] = 2.6018 [m/s] = number of velocity for the same solution
---
the difference of our solutions is in the space: 2.6018 [m] in X with 1[s] of reference in Z
my zero space is equal to your zero space with a factor of 2.6018 meters
or
the difference of our solutions is in the frequency: 2.6018 [Hz=1/s] in 1/Z with 1[m] of reference in X
my zero time is equal to your zero time with a factor of 2.6018 Hertz
---
0.0783-0.0043 = 0.0740 --> 0.0783 = 0 in a time of 605.0728
---
The point is that with one decimal there is not difference, the results are differents in the second decimal (1=2) and in the third decimal (6=1) for a total of 16=21 and this is 5 in 1000. A value of 0.005 like difference is a not difference if 5 is 0 in the third decimal. I think that the difference could be the definition of the zero value and this could be a not difference of results. Is a proportional factor, only one. And a proportional time factor is always present like union of two systems. I don’t know your algorithm, I hope this is a valid solution.

19 Aug 2009 MATLAB rooms KMN Color simulation of the neural instants physicity. Author: M P P, M

To improve a style is a long time way. If you say this with reference to the big number of rows I say yes, ok, the program is large, but in this time I have necessity of a large program, I must see the cyclicity and to find the numerical coincidence. To reduce the algorithm complexity is inevitable if I want to go forward with this model. I will learn the Matlab commands of important necessity and I’ll use the functions to reduce the lines when the model will be complete in the essential elements. Is a promise. Always if the model will be consider a reliable production. Thank you, if you have other words I will be happy to listen.

18 Aug 2009 0 - 1 test for chaos Implements the Gottwald - Melbourne 0 - 1 test for chaos Author: Paul Matthews P, M

Hi Paul,
what is the oversampled meaning?
0 = min caos
1 = max caos
The caos output is oversampled if there is one of a double condition or both. If my input vector or the random pc vector are in a “strange” form then there is oversampled warning. Reducing the maximum value of c the data is not oversampled. To reduce the max value of c is equal to reduce the possible circle combinations?
Very curious your program, regards.

13 Aug 2009 MIB: physics virtualizations Physics Equilibrium Mechanics Instant Author: M P P, M

^__________^
13 Aug 2009 perceptionP The not Bit. Author: M P P, M

This program is a model without input with purpose to show a mathematic mechanism; is a possible perceptive table because I have used a 19x19 table, dimension number equal at the voice-letters. In this file I have write the essential elements of the perceptive mechanism where ten numbers are the imaginary component. Inside .m file there are comments, not a lot but the strategy is showed. I’ll write other theory in the future and I’ll submit it inside project. In my website now there aren’t informations. My personal purpose is to build an identity-model, an inanimated system like simulation of the perceptive phenomena; for this there are two items, equals in the opposite coincidence. This program is an union way of 19 matter sounds and 10 values with the binary code, the computer language.
The importance, in my vision, is the symmetry. Bit and not Bit are always in a form of this type:
Number of record: 163
not Bit: 1 0 1 0 0 0 1 0
Number of record: 94
Bit: 0 1 0 1 1 1 0 1
If not Bit is Byte then the inverse not Bit is Bit and it is not Byte. In this way not Bit and Bit are Byte and not Byte, always 11111111.

13 Aug 2009 The Half: Pi NaN Values: 3 functions Author: M P P, M

?????????? boh
13 Aug 2009 The Midnight Safe Walking on the time Author: M P P, M

regards Mark, many many thanks
10 Aug 2009 The Half: Pi NaN Values: 3 functions Author: M P P, M

Ok, but I'm not understanding the problem.
05 Aug 2009 perceptionP The not Bit. Author: M P P, M

"the most recent research suggest that not selected spacetimes stay selected in certiginous space" ...... what research?

"the most recent research suggest that not selected spacetimes stay selected in certiginous space" ...... also I say this, program say this

"rendering this code outdated" ...... eheh, this is good... please, but please! this is a random pc execution in addition and it is a binary scheme

"rating." ................... put star put star...... to despise

02 Jul 2009 VFA Velocity Force Acceleration Author: M P P, M

02 Jul 2009 ILC Instants Letters Combinations Author: M P P, M

02 Jul 2009 inside Visual demonstration of a 3D system Author: M P P, M

02 Jul 2009 perception perceptive table Author: M P P, M

02 Jul 2009 Couple2 The not, the number of solutions. Author: M P P, M

02 Jul 2009 bi binary code Author: M P P, M

02 Jul 2009 NLNN2 1024 combinations and 2 input Author: M P P, M

02 Jul 2009 NLNN3 The quadruple: a static time is dynamic. Author: M P P, M

08 Jun 2009 ACCELERA Kg = 1 / Kg Author: M P P, M

Bozovic said:
what is that supposed to mean (among other nonsense):
Kg = 1 / Kg
Is 1 equal 4. The quadruplicity.
---
This is an example of quadruple time:
double verse in double operative way
---
start
2000-10-10
23:59:59
end
2000-11-01
08:30:00
result
distance in days, forward verse -> 22
distance in seconds, forward verse -> -52199
conclusion
more 21 days
less 22 days
or also
distance in days, forward verse -> 21
distance in seconds, forward verse -> 86400-52199
------
start
2000-11-01
08:30:00
end
2000-10-10
23:59:59
result
distance in days, behind verse -> 21
distance in seconds, behind verse -> 34201
conclusion
more 21 days
less 22 days
or also
distance in days, behind verse -> 22
distance in seconds, behind verse -> -(86400-34201)

05 May 2009 perception perceptive table Author: M P P, M

The procedural functions are not poor programming.
This submission is totally useless to you (you are not in the mind of anyone).
05 May 2009 Couple2 The not, the number of solutions. Author: M P P, M

The procedural functions are not poor programming.
This submission is totally useless to you (you are not in the mind of anyone).
04 May 2009 Couple2 The not, the number of solutions. Author: M P P, M

The zero utility of the program is questionable. We can write books and books and the zero utility of the programs will be always questionable. Good thing! A function without input and output is a ghost. But the function exist. The program variables are all input and all output. I think this. Maybe you are talking of command functions with a number of input and the logical output. Ok, this program is only function and I’ve write of the random execution strategy in the description.
04 May 2009 perception perceptive table Author: M P P, M

You could think in a good way. Where is the bizarre concept? 19 letters like sounds or 10 numbers or both or the table with the base elements? My vision is an image of numbers and I’m listening sounds. Is not necessary to have a super mega telescope or strange instrumentation to write a 19x19 program table. The indecipherable description is possible, but is a problem of you and the demonstration is your comment after 0,0000005 seconds after the administration submission. My descriptions has inside the passion for the research and for the Matlab language and is good thing a lecture with tranquility and calm. Anyhow if you find logical error inside the program structure I’m here to listen where, what, why, etc.
28 Apr 2009 Billiards Simulation of elastic collisions of balls of different sizes Author: Peter van Alem P, M

28 Apr 2009 Windscreen Wipers Simulation of a simple windscreen wiping model Author: Peter van Alem P, M

27 Apr 2009 ILC Instants Letters Combinations Author: M P P, M

“Ok theres isn't much point to posting additional data.”
Data
Data?
From where?
From who?
What is the posted list?
You can think this is true but it could be not true.. inanimated PC system is decisional….. secretary of nothing

26 Apr 2009 ILC Instants Letters Combinations Author: M P P, M

secretary............... I was position about number 100, with new classification I'm here, about 10........ envy is envy....... you could study in a better way the classifications......... secretary
08 Apr 2009 Equally spaced structured Point Cloud Cuboid generation Simple function to generate equally spaced point cloud forming a cuboid Author: Jveer P, M

No! Regards
01 Apr 2009 Fibonacci The following function generate the fibinacci series up to the sequence number m. Author: Shahab Anbarjafari P, M

Don’t listen the bad opinions, the despise-actions are symbols of envy. Big first position. Regards
09 Mar 2009 ACCELERA Kg = 1 / Kg Author: M P P, M

Yes Alexia, 1/Kg is an inverse matter if Kg is matter.
07 Mar 2009 ACCELERA Kg = 1 / Kg Author: M P P, M

27 Feb 2009 MOV Physics Movement Author: M P P, M

Double way.
The image way is always ok, impossible an image error.
In the voice way the errors are possible.
Is a life in a double system.
Numbers and letters. And their union in the half like perception, like equal symbol.

27 Feb 2009 MOV Physics Movement Author: M P P, M

Ok. If is so then all times that I say 1 Newton are 10 kilogram*meter/second^2 I’m in error, my statement is wrong. I don’t think this. How is possible an error in the base?! In the life representations is necessary to think at all possible statements; the error could exist if there is a reference but there is not error in the base statement (reference), the error could be in the future statements if the logic way go outside. The reference is a liberty. The references in the science-method are a standard but is not true that exist only the science-reference, this is not liberty. Like the light velocity. Is 300000 Km/s? Ok, this is the base. The comunity-reference. But also is true that light velocity is Infinite other values. If no all times that I think at the light I must think at one value. Like my name. If is so my name is one and only one. Is impossible to say to me Mark Marchetto Marcuccio and so on. No. The reference base is an arbitrary decision. And the logic ways in union with the reference must be an unity with the base (if no error). The reference is an opinion and the logic ways must be a logical unity with the base.

26 Feb 2009 MOV Physics Movement Author: M P P, M

ok, no problem
s=1 and s^2=1 is or is not s=s^2 ?????
I find true this statement
A=B and B=C is A=C

26 Feb 2009 MOV Physics Movement Author: M P P, M

No, Ken; second is kilogram and if second^2 is kilogram then second is second^2 because kilogram is kilogram. I understand your words but also you must think to my words; the base is the “number” of physics input and the letter-associations are a combinatorial-liberty. I don’t say my mass is 70 Kg, I say my weigth is 70.
26 Feb 2009 MOV Physics Movement Author: M P P, M

[s = Kg]
There is not error
The weight is the time staticity
The system stay up, don’t precipitate
Force = Weight * Altitude / Time^2 = Weight * Gravity
Force = Time / ( Weight * Altitude ) = 1 / ( Weight * Velocity )
Force = Force
Weight^2 * Gravity * Velocity = 1
[ Kg^2 * m^2 / s^3] = 1 --> [ m^2 / s ] = 1 --> [ m^2 = s ]
Conclusion
[ s = s ] --> [ Kg = m^2 ]
Or also
[ m / s^2 ] and [ m / ( s * Kg ) ] --> [ s = Kg ]
[ kg * m / s^2 ] and [ s / ( Kg * m ) ] --> [ Kg * m = s ] and [ s^2 = Kg * m ]
And so
[ s = s ] --> [ Kg = s^2 ]
With the union
[ Kg = Kg ] --> [ m^2 = s^2 ]
If I’ve a length, I’ve a time
The dimension of velocity
In the physics interpretations each formula is something, if no I could not think to it

24 Feb 2009 MOV Physics Movement Author: M P P, M

No. There are 3 input, the 3 most important physics input. I don't find error in this interpretation of the physics mechanism. The math is ok, the programming also and the science know sums and subtractions.

13 Feb 2009 speed Double system of velocity and reference Author: M P P, M

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