<?xml version="1.0" encoding="UTF-8"?>
<rss version="2.0">
  <channel>
    <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/156365</link>
    <title>MATLAB Central Newsreader - Re: calculating velocity in 3D space</title>
    <description>Feed for thread: Re: calculating velocity in 3D space</description>
    <language>en-us</language>
    <copyright>&amp;copy;1994-2012 by MathWorks, Inc.</copyright>
    <webmaster>webmaster@mathworks.com</webmaster>
    <generator>MATLAB Central Newsreader</generator>
    <docs>http://blogs.law.harvard.edu/tech/rss</docs>
    <ttl>60</ttl>
    <image>
      <title>MathWorks</title>
      <url>http://www.mathworks.com/images/membrane_icon.gif</url>
    </image>
    <item>
      <pubDate>Tue, 18 Sep 2007 18:25:40 -0400</pubDate>
      <title>Re: calculating velocity in 3D space</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/156365#392950</link>
      <author> Srikanth</author>
      <description>&lt;br&gt;
&amp;gt; something like:&lt;br&gt;
&amp;gt; sqrt((x0-x1)^2+(y0-y1)^2+(z0-z1)^2)/(t1-t0)&lt;br&gt;
&lt;br&gt;
Of course, this would give you more of a speed, rather than a&lt;br&gt;
velocity, since you don't have a direction... but if you wanted to&lt;br&gt;
find it with direction, all you need to do is to do a single&lt;br&gt;
differentiation in each axis separately. If you have a vector of&lt;br&gt;
points for each axis, you could use the diff command</description>
    </item>
  </channel>
</rss>

