MATLAB Central Newsreader - Jumping to the next interval

Jumping to the next interval

Archana Ananthanarayan — Thu, 15 May 2008 17:32:02 -0400

My problem goes like this :

I've a number line extending say from 0 to 600. I've divided
the line into equal intervals of 200 each. now i'm at 151 of
the 1st section. i need to jump to the next section say
number 201(of course - due to a condition), how do i
calculate the 1st number of the next interval? (that is 201)!

Thanks in Advance!

Re: Jumping to the next interval

helper — Thu, 15 May 2008 17:42:03 -0400

"Archana Ananthanarayan" <archana1985_ms@hotmail.com> wrote
in message <g0hs2i$ntm$1@fred.mathworks.com>...
> My problem goes like this :
>
> I've a number line extending say from 0 to 600. I've
divided
> the line into equal intervals of 200 each. now i'm at 151
of
> the 1st section. i need to jump to the next section say
> number 201(of course - due to a condition), how do i
> calculate the 1st number of the next interval? (that is
201)!
>
> Thanks in Advance!

First, if your line is from 0 to 600, you have 601 points,
not 600. So let's assume your line is from 1 to 600.

If you know your current point is cPt = 151, then you can
get the first point of the next section using:

firstNext = ceil((cPt-1)/200)*200 + 1

Note that I had to use (cPt-1) to handle the case where
cPt=200.

Re: Jumping to the next interval

Hosein — Thu, 15 May 2008 17:45:03 -0400

"Archana Ananthanarayan" <archana1985_ms@hotmail.com> wrote
in message <g0hs2i$ntm$1@fred.mathworks.com>...
> My problem goes like this :
>
> I've a number line extending say from 0 to 600. I've divided
> the line into equal intervals of 200 each. now i'm at 151 of
> the 1st section. i need to jump to the next section say
> number 201(of course - due to a condition), how do i
> calculate the 1st number of the next interval? (that is 201)!
>
> Thanks in Advance!

A=[.....] (1,600);
numcell(A); % (for example) =600
b=numcell(A)/number of lines
(line number)*b+1
I hope I understood your question rightly

Re: Jumping to the next interval

helper — Thu, 15 May 2008 17:54:02 -0400

> firstNext = ceil((cPt-1)/200)*200 + 1
>
> Note that I had to use (cPt-1) to handle the case where
> cPt=200.

Ooops. Looking at this again, I was wrong. No need to use
cPt-1

firstNext = ceil(cPt/200)*200 + 1

is sufficient.

Re: Jumping to the next interval

Archana Ananthanarayan — Thu, 15 May 2008 18:00:22 -0400

"helper " <spamless@nospam.com> wrote in message
<g0htbq$bhf$1@fred.mathworks.com>...
> > firstNext = ceil((cPt-1)/200)*200 + 1
> >
> > Note that I had to use (cPt-1) to handle the case where
> > cPt=200.
>
>
> Ooops. Looking at this again, I was wrong. No need to use
> cPt-1
>
> firstNext = ceil(cPt/200)*200 + 1
>
> is sufficient.

------------------------------------------------------------

thanks for all the replies! Its working!! Thanks a ton!

Re: Jumping to the next interval

Archana Ananthanarayan — Fri, 16 May 2008 11:04:02 -0400

"Archana Ananthanarayan" <archana1985_ms@hotmail.com> wrote
in message <g0htnm$4s9$1@fred.mathworks.com>...
> "helper " <spamless@nospam.com> wrote in message
> <g0htbq$bhf$1@fred.mathworks.com>...
> > > firstNext = ceil((cPt-1)/200)*200 + 1
> > >
> > > Note that I had to use (cPt-1) to handle the case where
> > > cPt=200.
> >
> >
> > Ooops. Looking at this again, I was wrong. No need to use
> > cPt-1
> >
> > firstNext = ceil(cPt/200)*200 + 1
> >
> > is
sufficie------------------------------------------------------------
>
> thanks for all the replies! Its working!! Thanks a ton!
>

-----------------------------------------------------------

The equation is not working when cPt assumes the values
150,250 etc.,

How to solve this?

Re: Jumping to the next interval

Nitin Chhabra — Fri, 16 May 2008 11:15:04 -0400

"Archana Ananthanarayan" <archana1985_ms@hotmail.com>
wrote in message <g0jpn2$p6n$1@fred.mathworks.com>...
> "Archana Ananthanarayan" <archana1985_ms@hotmail.com>
wrote
> in message <g0htnm$4s9$1@fred.mathworks.com>...
> > "helper " <spamless@nospam.com> wrote in message
> > <g0htbq$bhf$1@fred.mathworks.com>...
> > > > firstNext = ceil((cPt-1)/200)*200 + 1
> > > >
> > > > Note that I had to use (cPt-1) to handle the case
where
> > > > cPt=200.
> > >
> > >
> > > Ooops. Looking at this again, I was wrong. No need
to use
> > > cPt-1
> > >
> > > firstNext = ceil(cPt/200)*200 + 1
> > >
> > > is
> sufficie-------------------------------------------------
-----------
> >
> > thanks for all the replies! Its working!! Thanks a ton!
> >
>
> ---------------------------------------------------------
--
>
> The equation is not working when cPt assumes the values
> 150,250 etc.,
>
> How to solve this?
>
Hi,

what exactly is the problem ??
i checked for 150/250 etc and above gives correct
result....
Please tell the error message and result u get .

with reagrds,
Nitin

Re: Jumping to the next interval

Archana Ananthanarayan — Fri, 16 May 2008 11:29:02 -0400

> Hi,
>
> what exactly is the problem ??
> i checked for 150/250 etc and above gives correct
> result....
> Please tell the error message and result u get .
>
> with reagrds,
> Nitin
>
--------------------------------------------------------

Its working now!! i will get back when i encounter any
error. thanks!