constructing a 3D array (using permute?)

Dave Brackett — Tue, 22 Jul 2008 17:45:06 -0400

I have some code as follows:

a=rand(50,16)
b=pi*a.^2

f=1:100
w=2*pi*f

c=sqrt((w'.*b)/(pi))

This returns an error stating that the matrix dimensions
must agree as would be expected because w' is [100 1] and b
is [50 16].

My question is, how can I assemble a 3D array of size [100
16 50] to be stored as c, from w' and b?

I think permute is needed but can't get it to do what I want.
Hopefully you can help. Thanks.

Re: constructing a 3D array (using permute?)

Roger Stafford — Tue, 22 Jul 2008 19:04:03 -0400

"Dave Brackett" <davebrackett@hotmail.com> wrote in message <g656b2
$4o1$1@fred.mathworks.com>...
> I have some code as follows:
>
> a=rand(50,16)
> b=pi*a.^2
>
> f=1:100
> w=2*pi*f
>
> c=sqrt((w'.*b)/(pi))
>
>
> This returns an error stating that the matrix dimensions
> must agree as would be expected because w' is [100 1] and b
> is [50 16].
>
> My question is, how can I assemble a 3D array of size [100
> 16 50] to be stored as c, from w' and b?
>
> I think permute is needed but can't get it to do what I want.
> Hopefully you can help. Thanks.

I believe you need to first use 'shiftdim' by -1 with b, producing a three-
dimensional array with a first dimension singleton. Then apply 'bsxfun' with
"@times" using this and w/pi.

Roger Stafford

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constructing a 3D array (using permute?)

Re: constructing a 3D array (using permute?)