How to reverse the algorithm

Neo — Fri, 28 Nov 2008 22:44:02 -0500

N=length(s)
T=1/fs;
t=0:T:(N-1)*T;
fs=fs

L=100; % length of frames
nframes=floor(length(s)/L) % floor gives integer number of frames
energy=zeros(1,nframes); % An energy array of zeros

for i=1:nframes
    index=L*(i-1);
    sum=0;
    for j=1:L;
        sum=sum+s(index+j)*s(index+j); %squaring each frame
    end
    energy(i)=sum;
end

m=max(energy);
c=0.1;
z=energy(1)+c*(m-energy(1));

for i=1:L
    if energy(i)>z
        startindex=i
    end
end

Hi I have this program to find the first frame where energy is above Z, hence found the start of a word. I now need to reverse the energy matrix and perform the algorithm again to find the end of the word.

Can anyone please help with this??

I think using energy(end:-1:1) reverses the energy values.

Any help is much appreciated

Re: How to reverse the algorithm

Jan Simon — Sat, 29 Nov 2008 01:45:04 -0500

Dear Neo!

> for i=1:L
> if energy(i)>z
> startindex=i
> end
> end
>
> Hi I have this program to find the first frame where energy is above Z, hence found the start of a word. I now need to reverse the energy matrix and perform the algorithm again to find the end of the word.

Instead of the loop, you can please FIND to find start and end points:
  Index = find(energy > z);
  startIndex = Index(1);
  endIndex = Index(end);

Jan

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How to reverse the algorithm

Re: How to reverse the algorithm