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    <title>MATLAB Central Newsreader - repace NaN with zero</title>
    <description>Feed for thread: repace NaN with zero</description>
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    <item>
      <pubDate>Tue, 16 Jun 2009 02:54:02 -0400</pubDate>
      <title>repace NaN with zero</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/253783#657605</link>
      <author>Diego Lass</author>
      <description>Hi&lt;br&gt;
I want to replace NaN in the current matrix with 0, what is the fastest way? &lt;br&gt;
&amp;nbsp;&lt;br&gt;
A = [ 1 2 NaN; NaN 2 3; NaN NaN 100 ]&lt;br&gt;
&lt;br&gt;
A =&lt;br&gt;
&lt;br&gt;
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;1     2   NaN&lt;br&gt;
&amp;nbsp;&amp;nbsp;&amp;nbsp;NaN     2     3&lt;br&gt;
&amp;nbsp;&amp;nbsp;&amp;nbsp;NaN   NaN   100&lt;br&gt;
&lt;br&gt;
Thanks&lt;br&gt;
Diego</description>
    </item>
    <item>
      <pubDate>Tue, 16 Jun 2009 03:14:02 -0400</pubDate>
      <title>repace NaN with zero</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/253783#657606</link>
      <author>John D'Errico</author>
      <description>&quot;Diego Lass&quot; &amp;lt;dlISCool@gmail.com&amp;gt; wrote in message &amp;lt;h171ga$inm$1@fred.mathworks.com&amp;gt;...&lt;br&gt;
&amp;gt; Hi&lt;br&gt;
&amp;gt; I want to replace NaN in the current matrix with 0, what is the fastest way? &lt;br&gt;
&amp;gt;  &lt;br&gt;
&amp;gt; A = [ 1 2 NaN; NaN 2 3; NaN NaN 100 ]&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; A =&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt;      1     2   NaN&lt;br&gt;
&amp;gt;    NaN     2     3&lt;br&gt;
&amp;gt;    NaN   NaN   100&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; Thanks&lt;br&gt;
&amp;gt; Diego&lt;br&gt;
&lt;br&gt;
A(isnan(A)) = 0;</description>
    </item>
    <item>
      <pubDate>Tue, 16 Jun 2009 03:20:18 -0400</pubDate>
      <title>repace NaN with zero</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/253783#657609</link>
      <author>Diego Lass</author>
      <description>OK I got it&lt;br&gt;
k = find(isnan(A))';&lt;br&gt;
A(k) = 0;&lt;br&gt;
&lt;br&gt;
Diego&lt;br&gt;
&lt;br&gt;
&lt;br&gt;
&quot;Diego Lass&quot; &amp;lt;dlISCool@gmail.com&amp;gt; wrote in message &amp;lt;h171ga$inm$1@fred.mathworks.com&amp;gt;...&lt;br&gt;
&amp;gt; Hi&lt;br&gt;
&amp;gt; I want to replace NaN in the current matrix with 0, what is the fastest way? &lt;br&gt;
&amp;gt;  &lt;br&gt;
&amp;gt; A = [ 1 2 NaN; NaN 2 3; NaN NaN 100 ]&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; A =&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt;      1     2   NaN&lt;br&gt;
&amp;gt;    NaN     2     3&lt;br&gt;
&amp;gt;    NaN   NaN   100&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; Thanks&lt;br&gt;
&amp;gt; Diego</description>
    </item>
    <item>
      <pubDate>Tue, 16 Jun 2009 11:15:02 -0400</pubDate>
      <title>Re: repace NaN with zero</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/253783#657694</link>
      <author>Loren Shure</author>
      <description>In article &amp;lt;h1731i$pue$1@fred.mathworks.com&amp;gt;, dlISCool@gmail.com says...&lt;br&gt;
&amp;gt; OK I got it&lt;br&gt;
&amp;gt; k = find(isnan(A))';&lt;br&gt;
&amp;gt; A(k) = 0;&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; Diego&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &quot;Diego Lass&quot; &amp;lt;dlISCool@gmail.com&amp;gt; wrote in message &amp;lt;h171ga$inm$1@fred.mathworks.com&amp;gt;...&lt;br&gt;
&amp;gt; &amp;gt; Hi&lt;br&gt;
&amp;gt; &amp;gt; I want to replace NaN in the current matrix with 0, what is the fastest way? &lt;br&gt;
&amp;gt; &amp;gt;  &lt;br&gt;
&amp;gt; &amp;gt; A = [ 1 2 NaN; NaN 2 3; NaN NaN 100 ]&lt;br&gt;
&amp;gt; &amp;gt; &lt;br&gt;
&amp;gt; &amp;gt; A =&lt;br&gt;
&amp;gt; &amp;gt; &lt;br&gt;
&amp;gt; &amp;gt;      1     2   NaN&lt;br&gt;
&amp;gt; &amp;gt;    NaN     2     3&lt;br&gt;
&amp;gt; &amp;gt;    NaN   NaN   100&lt;br&gt;
&amp;gt; &amp;gt; &lt;br&gt;
&amp;gt; &amp;gt; Thanks&lt;br&gt;
&amp;gt; &amp;gt; Diego&lt;br&gt;
&amp;gt; &lt;br&gt;
&lt;br&gt;
No need for the overhead with find.  Follow John D's advice.&lt;br&gt;
&lt;br&gt;
-- &lt;br&gt;
Loren&lt;br&gt;
&lt;a href=&quot;http://blogs.mathworks.com/loren&quot;&gt;http://blogs.mathworks.com/loren&lt;/a&gt;</description>
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