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    <title>MATLAB Central Newsreader - Third order differential equation</title>
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    <item>
      <pubDate>Tue, 03 Nov 2009 18:52:02 -0500</pubDate>
      <title>Third order differential equation</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/264864#691801</link>
      <author>Sabil Ahmed</author>
      <description>Hi,&lt;br&gt;
&lt;br&gt;
I need to know how to solve the following equation via matlab:&lt;br&gt;
&lt;br&gt;
f.f'''+k.f'.f''=0&lt;br&gt;
&lt;br&gt;
where f is a function of x: f(x)&lt;br&gt;
and k is a constant&lt;br&gt;
&lt;br&gt;
Can it even be solved at all?&lt;br&gt;
&lt;br&gt;
Regards,&lt;br&gt;
&lt;br&gt;
Uchiha Sama</description>
    </item>
    <item>
      <pubDate>Fri, 06 Nov 2009 08:08:54 -0500</pubDate>
      <title>Re: Third order differential equation</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/264864#692616</link>
      <author>Torsten Hennig</author>
      <description>&amp;gt; Hi,&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; I need to know how to solve the following equation&lt;br&gt;
&amp;gt; via matlab:&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; f.f'''+k.f'.f''=0&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; where f is a function of x: f(x)&lt;br&gt;
&amp;gt; and k is a constant&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; Can it even be solved at all?&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; Regards,&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; Uchiha Sama&lt;br&gt;
&lt;br&gt;
Divide your equation by f'*f''' to get &lt;br&gt;
log(f(t)/f(t0)) = -k*log(f''(t)/f''(t0))&lt;br&gt;
or&lt;br&gt;
f(t)/f(t0) = (f''(t)/f''(t0))^(-k)&lt;br&gt;
or&lt;br&gt;
f(t)*f''(t0)^(-k) - f''(t)^(-k)*f(t0) = 0.&lt;br&gt;
Now setting f = y, f'=z gives the system&lt;br&gt;
y' = z&lt;br&gt;
z' = (y*f''(t0)^(-k)/f(t0))^(-1/k)&lt;br&gt;
which can be solved easily using one of the solvers&lt;br&gt;
of the ODE suite.&lt;br&gt;
&lt;br&gt;
Best wishes&lt;br&gt;
Torsten.</description>
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