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Sun, 15 Aug 2010 15:55:06 +0000
Erlang B
http://www.mathworks.com/matlabcentral/newsreader/view_thread/289377#771599
Michael
Hello,<br>
<br>
anyone could help me regarding this machine problem?<br>
It is about the Erlang B Traffic Formula which:<br>
<br>
Pb = A^c / factorial c * (summation of c(k=0) A^k / K!)<br>
<br>
Pb is given and c is given, now i need to solve for A in erlangs to solve the Erlang B table up to C=20. The (summation....) can be further simplify to its maclauren equivalent of e^A. hope anyone can help.thanks<br>
<br>
Mike

Sun, 15 Aug 2010 17:58:03 +0000
Re: Erlang B
http://www.mathworks.com/matlabcentral/newsreader/view_thread/289377#771631
Roger Stafford
"Michael " <mikeinmars@yahoo.com> wrote in message <i492kq$375$1@fred.mathworks.com>...<br>
> Hello,<br>
> <br>
> anyone could help me regarding this machine problem?<br>
> It is about the Erlang B Traffic Formula which:<br>
> <br>
> Pb = A^c / factorial c * (summation of c(k=0) A^k / K!)<br>
> <br>
> Pb is given and c is given, now i need to solve for A in erlangs to solve the Erlang B table up to C=20. The (summation....) can be further simplify to its maclauren equivalent of e^A. hope anyone can help.thanks<br>
> <br>
> Mike<br>
          <br>
According to <a href="http://en.wikipedia.org/wiki/Erlang_">http://en.wikipedia.org/wiki/Erlang_</a>(unit) that summation you have should be in the denominator and the summation should range from k = 0 to k = c.<br>
<br>
If you multiply both sides of the equation by that summation and subtract one side from the other, you get a polynomial equation in A. You can use matlab's roots function to solve for the roots of that polynomial. The degree of the polynomial is c so you will get that many roots and it will be your task to pick out the right one. Probably most of them, maybe all but one, will either be complexvalued or negative and therefore easy to discard.<br>
<br>
Roger Stafford