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    <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/77657</link>
    <title>MATLAB Central Newsreader - simple but urgent</title>
    <description>Feed for thread: simple but urgent</description>
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    <ttl>60</ttl>
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    <item>
      <pubDate>Wed, 06 Oct 2004 12:50:38 -0400</pubDate>
      <title>simple but urgent</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/77657#197272</link>
      <author>laux5101@gmx.net (Lex)</author>
      <description>Hello,&lt;br&gt;
&lt;br&gt;
x=zeros(1000,1);&lt;br&gt;
&lt;br&gt;
for i=1:length(Summe)&lt;br&gt;
%   for j=1:5&lt;br&gt;
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;if Summe(i,1)&amp;gt;=25, x=Summe(i,:)&lt;br&gt;
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&lt;br&gt;
%         &amp; (B(j,1) &amp;gt;= 0) &amp;gt;= 3 ; &lt;br&gt;
end&lt;br&gt;
end&lt;br&gt;
&lt;br&gt;
Matlab gives me for x just one value (1x1), but there a many values in&lt;br&gt;
'Summe' which are &amp;gt;=0 ???&lt;br&gt;
&lt;br&gt;
And how can I predefine x without knowing the exact dimension of x&lt;br&gt;
(lines) in advance?&lt;br&gt;
&amp;nbsp;</description>
    </item>
    <item>
      <pubDate>Wed, 06 Oct 2004 15:52:14 -0400</pubDate>
      <title>Re: simple but urgent</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/77657#197299</link>
      <author>Waldemar Krzok</author>
      <description>&lt;br&gt;
&lt;br&gt;
Lex wrote:&lt;br&gt;
&amp;gt; Hello,&lt;br&gt;
&amp;gt; &lt;br&gt;
x=[];&lt;br&gt;
&lt;br&gt;
for i=1:length(Summe)&lt;br&gt;
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;if Summe(i,1)&amp;gt;=25&lt;br&gt;
	 x=[x; Summe(i,:)];&lt;br&gt;
&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;end %if&lt;br&gt;
end %for&lt;br&gt;
&lt;br&gt;
try above. x will have size (number_gt_25,dim2_of_Summe)&lt;br&gt;
&lt;br&gt;
Waldemar</description>
    </item>
    <item>
      <pubDate>Wed, 06 Oct 2004 10:03:51 -0400</pubDate>
      <title>Re: simple but urgent</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/77657#197305</link>
      <author>Brett Shoelson</author>
      <description>&lt;br&gt;
&quot;Lex&quot; &amp;lt;laux5101@gmx.net&amp;gt; wrote in message news:fz21vkbs48zl@legacy...&lt;br&gt;
&amp;gt; Hello,&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt; x=zeros(1000,1);&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt; for i=1:length(Summe)&lt;br&gt;
&amp;gt; %   for j=1:5&lt;br&gt;
&amp;gt;        if Summe(i,1)&amp;gt;=25, x=Summe(i,:)&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt; %         &amp; (B(j,1) &amp;gt;= 0) &amp;gt;= 3 ;&lt;br&gt;
&amp;gt; end&lt;br&gt;
&amp;gt; end&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt; Matlab gives me for x just one value (1x1), but there a many values in&lt;br&gt;
&amp;gt; 'Summe' which are &amp;gt;=0 ???&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt; And how can I predefine x without knowing the exact dimension of x&lt;br&gt;
&amp;gt; (lines) in advance?&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt;&lt;br&gt;
&lt;br&gt;
Hi Lex,&lt;br&gt;
You're clearly new to ML, and probably to programming. I strongly urge you &lt;br&gt;
to read the getting started docs for this program. Besides Waldemar's &lt;br&gt;
solution to your problem, ML has many ways of making dealing with these &lt;br&gt;
kinds of problems a breeze. For instance:&lt;br&gt;
&lt;br&gt;
x = Summe(Summe&amp;gt;=25);&lt;br&gt;
&lt;br&gt;
Cheers,&lt;br&gt;
Brett </description>
    </item>
    <item>
      <pubDate>Wed, 06 Oct 2004 17:26:14 -0400</pubDate>
      <title>Re: simple but urgent</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/77657#197336</link>
      <author>Waldemar Krzok</author>
      <description>&lt;br&gt;
&amp;gt;&amp;gt;x=zeros(1000,1);&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;for i=1:length(Summe)&lt;br&gt;
&amp;gt;&amp;gt;%   for j=1:5&lt;br&gt;
&amp;gt;&amp;gt;       if Summe(i,1)&amp;gt;=25, x=Summe(i,:)&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;%         &amp; (B(j,1) &amp;gt;= 0) &amp;gt;= 3 ;&lt;br&gt;
&amp;gt;&amp;gt;end&lt;br&gt;
&amp;gt;&amp;gt;end&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;Matlab gives me for x just one value (1x1), but there a many values in&lt;br&gt;
&amp;gt;&amp;gt;'Summe' which are &amp;gt;=0 ???&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;And how can I predefine x without knowing the exact dimension of x&lt;br&gt;
&amp;gt;&amp;gt;(lines) in advance?&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; Hi Lex,&lt;br&gt;
&amp;gt; You're clearly new to ML, and probably to programming. I strongly urge you &lt;br&gt;
&amp;gt; to read the getting started docs for this program. Besides Waldemar's &lt;br&gt;
&amp;gt; solution to your problem, ML has many ways of making dealing with these &lt;br&gt;
&amp;gt; kinds of problems a breeze. For instance:&lt;br&gt;
&amp;gt; &lt;br&gt;
&amp;gt; x = Summe(Summe&amp;gt;=25);&lt;br&gt;
&lt;br&gt;
&lt;br&gt;
he needs to compare Summe(:,1), but there are still many ways to do it.&lt;br&gt;
&lt;br&gt;
Waldemar</description>
    </item>
    <item>
      <pubDate>Wed, 06 Oct 2004 11:36:32 -0400</pubDate>
      <title>Re: simple but urgent</title>
      <link>http://www.mathworks.com/matlabcentral/newsreader/view_thread/77657#197351</link>
      <author>Brett Shoelson</author>
      <description>&lt;br&gt;
&quot;Waldemar Krzok&quot; &amp;lt;waldemar.krzok@ukbf.fu-berlin.de&amp;gt; wrote in message &lt;br&gt;
news:41640E96.9070106@ukbf.fu-berlin.de...&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;x=zeros(1000,1);&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;for i=1:length(Summe)&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;%   for j=1:5&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;       if Summe(i,1)&amp;gt;=25, x=Summe(i,:)&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;%         &amp; (B(j,1) &amp;gt;= 0) &amp;gt;= 3 ;&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;end&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;end&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;Matlab gives me for x just one value (1x1), but there a many values in&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;'Summe' which are &amp;gt;=0 ???&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;And how can I predefine x without knowing the exact dimension of x&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;(lines) in advance?&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt; Hi Lex,&lt;br&gt;
&amp;gt;&amp;gt; You're clearly new to ML, and probably to programming. I strongly urge &lt;br&gt;
&amp;gt;&amp;gt; you to read the getting started docs for this program. Besides Waldemar's &lt;br&gt;
&amp;gt;&amp;gt; solution to your problem, ML has many ways of making dealing with these &lt;br&gt;
&amp;gt;&amp;gt; kinds of problems a breeze. For instance:&lt;br&gt;
&amp;gt;&amp;gt;&lt;br&gt;
&amp;gt;&amp;gt; x = Summe(Summe&amp;gt;=25);&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt; he needs to compare Summe(:,1), but there are still many ways to do it.&lt;br&gt;
&amp;gt;&lt;br&gt;
&amp;gt; Waldemar&lt;br&gt;
&amp;gt;&lt;br&gt;
&lt;br&gt;
I guess I just don't understand his question. Or what Summe is, or what he's &lt;br&gt;
trying to compare.&lt;br&gt;
Brett </description>
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