Path: news.mathworks.com!not-for-mail From: Alan Weiss <aweiss@mathworks.com> Newsgroups: comp.soft-sys.matlab Subject: Re: Radius of convergence? Date: Mon, 09 Feb 2009 09:54:23 -0500 Organization: The MathWorks, Inc. Lines: 17 Message-ID: <gmpg2v$ba9$1@fred.mathworks.com> References: <gmp919$5sd$1@fred.mathworks.com> NNTP-Posting-Host: weissa.dhcp.mathworks.com Mime-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit X-Trace: fred.mathworks.com 1234191263 11593 172.31.57.119 (9 Feb 2009 14:54:23 GMT) X-Complaints-To: news@mathworks.com NNTP-Posting-Date: Mon, 9 Feb 2009 14:54:23 +0000 (UTC) User-Agent: Thunderbird 2.0.0.19 (Windows/20081209) In-Reply-To: <gmp919$5sd$1@fred.mathworks.com> Xref: news.mathworks.com comp.soft-sys.matlab:517060 Joerg Buchholz wrote: > syms x > f = sin (x) > t = taylor (f) > > returns the Maclaurin approximation of the sine function. Is there a way to compute the radius of convergence of the approximation analytically? Hi, I am not sure I understand your question. Radius of convergence usually applies to functions whose Taylor series can diverge if more terms are taken. It is well known that the radius of convergence of a Taylor series for the sine function is infinity. However, perhaps you are asking if there is a way for the Symbolic Math Toolbox to analytically demonstrate that the radius is infinity. Is that your question? Alan Weiss MATLAB mathematical toolbox documentation