Path: news.mathworks.com!not-for-mail
From: "James Carter" <jimctr@msn.com>
Newsgroups: comp.soft-sys.matlab
Subject: Basic Matlab Question
Date: Mon, 16 Nov 2009 23:46:01 +0000 (UTC)
Organization: Leupold &#38; Stevens Inc
Lines: 12
Message-ID: <hdso7p$sh5$1@fred.mathworks.com>
Reply-To: "James Carter" <jimctr@msn.com>
NNTP-Posting-Host: webapp-05-blr.mathworks.com
Content-Type: text/plain; charset="ISO-8859-1"
Content-Transfer-Encoding: 8bit
X-Trace: fred.mathworks.com 1258415161 29221 172.30.248.35 (16 Nov 2009 23:46:01 GMT)
X-Complaints-To: news@mathworks.com
NNTP-Posting-Date: Mon, 16 Nov 2009 23:46:01 +0000 (UTC)
X-Newsreader: MATLAB Central Newsreader 453088
Xref: news.mathworks.com comp.soft-sys.matlab:585612


I have a 32 x 1300 2D array, lets call it S.  I know I can pick off a particular row with the following argument: A = S(1,:); which gives me a 1 x 1300 array from the first 
row of the 2D array.  I want every row assigned to a new indexed array, so I would start off with

for n = 1:rows
A(n) = S(n,:);
end

This doesn't work because of a dimensional mismatch.   I'm not really trying to define
a dimension but simply declare a unique identifier.   How am I able to assign rows 
such that I can put them in A(1), A(2), etc., all with the dimension 1 x 1300.  

Thanks!