Path: news.mathworks.com!not-for-mail From: <HIDDEN> Newsgroups: comp.soft-sys.matlab Subject: Re: eigenvector equation doubt Date: Mon, 13 Sep 2010 15:00:23 +0000 (UTC) Organization: The MathWorks, Inc. Lines: 20 Message-ID: <i6lea7$764$1@fred.mathworks.com> References: <i6lck9$e6j$1@fred.mathworks.com> Reply-To: <HIDDEN> NNTP-Posting-Host: webapp-02-blr.mathworks.com Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-Trace: fred.mathworks.com 1284390023 7364 172.30.248.37 (13 Sep 2010 15:00:23 GMT) X-Complaints-To: news@mathworks.com NNTP-Posting-Date: Mon, 13 Sep 2010 15:00:23 +0000 (UTC) X-Newsreader: MATLAB Central Newsreader 1187260 Xref: news.mathworks.com comp.soft-sys.matlab:669613 "shahnaz fatima" <shahnaz1981fat@gmail.com> wrote in message <i6lck9$e6j$1@fred.mathworks.com>... > any body here plz help me with the eigen equation. > > suppose i have an eigen equation > > Wy=lamda Dy; > > does that mean that the eigen vectors y are the eigen vectors of D-W > > plz explain.its urgent - - - - - - - - No it doesn't mean that. If D is a general square matrix, what it means is that the y vector is a generalized eigenvector as given by [Y,L] = eig(W,D) with y one of the columns of Y and lambda a corresponding generalized eigenvalue in L. Also if D is invertible, it means that y is an eigenvector of inv(D)*W with lambda as the corresponding eigenvalue. See the documentation for eig (where A and B correspond to your W and D.) Roger Stafford