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Subject: Re: ode with definite integral
Date: Thu, 30 Jun 2011 07:44:10 +0000 (UTC)
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"Grzegorz Knor" wrote in message <iuh6ma$ggi$1@newscl01ah.mathworks.com>...
> Hello,
> I wonder how to solve such a task:
> Suppose we want to solve a differential equation in the form:
> dy/dt = f(t) = exp(-te)
> where:
> te = \int from 0 to t (2^(y/10)) dt
> Is it possible to do it with Matlab ode solvers?
> 
> Best regards
> Grzegorz
- - - - - - - - -
  Yes, that can easily be done with an ode solver.  Define

 te(t) = int('2^(y(s)/10)','s',0,t)

Then we have

 dte(t)/dt = 2^(y(t)/10)

and

 dy(t)/dt = exp(-te(t))

so this is in the proper form to be solved with an ode solver.  You must of course arrange that te(0) = 0.  The initial value, y(0), is up to you.

Roger Stafford