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From: "Julio Gonzalez" <julio@part-time-scientists.com>
Newsgroups: comp.soft-sys.matlab
Subject: Re: While loop fails
Date: Sat, 22 Oct 2011 01:15:30 +0000 (UTC)
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"ScottB" wrote in message <j7siql\$37t\$1@newscl01ah.mathworks.com>...
> "Julio Gonzalez" <julio@part-time-scientists.com> wrote in message <j7sh2e\$q77\$1@newscl01ah.mathworks.com>...
> > I am trying to get a while loop to work. I have an integer T, that I converted to double using the function double. But when I print the value of double T, it shows T as an integer and not as a double. Therefore my loop fails. This is the code:
> >
> > Ti=2
> > T = double(T);
> > to= 0.0000;
> >
> > while (T<=to)
> >     to = to+0.1;
> >     %some code here.....
> > end
> >
> > the loop end at to=2.0000; it should end at 2.1000
> >
> > Is there any other way to fix this problems besides T=2*(1+eps)?
> >
> > Regards
> >
> > Julio
> > University of Liverpool
>
> Julio,
>
> T is a double already. I think your example is supposed to look like this:
>
> T=2
> to= 0.0000;
>
> while (to<=T)
>     to = to+0.1
>     %some code here.....
> end
>
> The loop stops when to = 2. What are you trying to do?
>
> ScottB
Hi Scott,

It is a simple while loop.  T is integer equal to 2; "to" increments 0.1 on each pass of the loop until it reaches 2.0. It works while (to<2). But it fails in the checking when
to = T = 2.

If I print T, I can see only the number "2"... No decimal point.

I can not make T double even if I explicitly makes it double. But if I apply T = 2*(1+eps) then I can see now T= 2.0000 and the while loop terminates correctly...

Julio
```