Path: news.mathworks.com!not-for-mail From: <HIDDEN> Newsgroups: comp.soft-sys.matlab Subject: Re: Solving complex number Date: Tue, 15 Jan 2013 08:02:08 +0000 (UTC) Organization: The MathWorks, Inc. Lines: 21 Message-ID: <kd32dv$fct$1@newscl01ah.mathworks.com> References: <kd10cs$cv6$1@newscl01ah.mathworks.com> Reply-To: <HIDDEN> NNTP-Posting-Host: www-00-blr.mathworks.com Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit X-Trace: newscl01ah.mathworks.com 1358236928 15773 172.30.248.45 (15 Jan 2013 08:02:08 GMT) X-Complaints-To: news@mathworks.com NNTP-Posting-Date: Tue, 15 Jan 2013 08:02:08 +0000 (UTC) X-Newsreader: MATLAB Central Newsreader 3799640 Xref: news.mathworks.com comp.soft-sys.matlab:786562 "Salvinder " <salvinder@gmail.com> wrote in message <kd10cs$cv6$1@newscl01ah.mathworks.com>... > Hie, > > I've got a matrix of 2X2 as shown below: > > [ 0.6 0.4; 0.7 0.3]^n > > when I change the value of n based on integer's I have no problem because I'll get the desired answer, but when n becomes decimal numbers such as 1.2 or 1.25, the solution will have a complex number as a solution. For example the solution would look as shown below: > > [ 0.2 + 0.034i 0.6 - 0.2i ; 0.4 - 0.03i 0.7+0.4i] > > Is there any possible way of removing the complex numbers? > > Thanks, No. Your matrix is diagonizable, but has one negative eigenvalue (-0.1). Thus complex entries are to be expected when taking a non-integer power of it. Best wishes Torsten.