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Subject: Re: Alternative solution for NAN
Date: Wed, 27 Feb 2013 10:47:07 +0000 (UTC)
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"Carl  S." wrote in message <kgkmon$aeo$1@newscl01ah.mathworks.com>...
> "Torsten" wrote in message <kgklbh$6ph$1@newscl01ah.mathworks.com>...
> > "Carl  S." wrote in message <kgki2g$rie$1@newscl01ah.mathworks.com>...
> > > The following code gives NAN (Not a Number) values
> > > [U,D]=eig(N);  
> > > 
> > > To solve this problem, I wrote that
> > > while(det(N) == 0)
> > >      N=(1e-10.*randi(1,size(N)))*eye(size(N));
> > > end
> > > 
> > > But, the loop does not stop
> > 
> > Your matrix N within the loop always has determinant (1e-10)^(size(N))
> > which may become very small if N is large.
> > 
> >  :( Are there any alternative solution instead of this loop to solve the NAN problem ?
> > 
> > Depends on the original matrix N.
> > 
> > Best wishes
> > Torsten.
> 
> Dear Torsten,
> The matrix N has standard deviation values of grayscale images. So, it changes for each image. How to solve the NAN problem in this case ?

Did you check whether the matrix N already contains NaN values ?

Best wishes
Torsten.