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Subject: Re: Averaging in 3rd dimension in a loop
Date: Fri, 15 Mar 2013 15:13:06 +0000 (UTC)
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"Max" wrote in message <khv9h7$49f$1@newscl01ah.mathworks.com>...
> Dears, 
> 
> I want to take average of long data array in 3rd dimension, but I am not getting the wanted result. Lets say I have A = rand(8,8,10);  
> Now averaging (mean) over let say each 2 values in 3rd dimension, it should give me size 8x8x5. 
> 
> I did this, but doesn't work
> A1 = [];
> for m = 1: 2: 10
>     A1 = [A1; mean(A(:,:,m:m+4),3)];
> end
> 
> Any help in this regard would highly appreciated. Thanks 
==============

Use the function below.

  A1=downsampn(A,[1,1,2]);


function M=downsampn(M,bindims)
%DOWNSAMPN - simple tool for downsampling n-dimensional nonsparse arrays
%
%  M=downsampn(M,bindims)
%
%in:
%
% M: an array
% bindims: a vector of integer binning dimensions
%
%out:
%
% M: the downsized array

nn=length(bindims);

[sz{1:nn}]=size(M); %M is the original array
sz=[sz{:}];


newdims=sz./bindims;

args=num2cell([bindims;newdims]);

M=reshape(M,args{:});

for ii=1:nn


 M=mean(M,2*ii-1);
 
end

M=reshape(M,newdims);