Thread Subject: how to do this without for loops?

Hi,

I have two vectors, v1 and v2, with possibly different number of
elements.
I want to compute a matrix D without using for loops, that stores the
difference:

so that
D(i,j) = v1(i) - v2(j)

Can anyone show me how to do this without for loops?
Thanks!
bahoo

bahoo:
<SNIP in search of a mesh

> D(i,j) = v1(i) - v2(j)
> Can anyone show me how to do this without for loops...

two of the many solutions

     a=1:5;
     b=[10,100];
% one
     [x,y]=meshgrid(a,b);
     r1=x-y;
% two
     r2=arrayfun(@(x) x-b,a,'uni',false);
     r2=cat(1,r2{:}).';
% the result
     r1
     isequal(r1,r2)

us

In article <1186694781.588924.201810@x35g2000prf.googlegroups.com>,
b83503104@yahoo.com says...
> Hi,
>
> I have two vectors, v1 and v2, with possibly different number of
> elements.
> I want to compute a matrix D without using for loops, that stores the
> difference:
>
> so that
> D(i,j) = v1(i) - v2(j)
>
> Can anyone show me how to do this without for loops?
> Thanks!
> bahoo
>
>

I make sure one is a column and the other a row inside the call to
bsxfun.

c1 = bsxfun(@minus,a(:),b(:).')

--
Loren
http://blogs.mathworks.com/loren/