Thread Subject: greater than or less than

I am writing a program that is going to plot a function. I
don't know the correct way to write a matlab function that
will: 10<=x<=1.2*y (1)

y=3.2

Whenever I type in the code as is, MatLab wants me to
define x. I am going to put x in another function, ex
2.7+x=t. I am going to plot x vs. t. I just don't know how
to tell MatLab to take values in between the range of the
above stated values in equation (1).

On 30 ago, 07:03, "Ender " <jr...@msstate.edu> wrote:
> I am writing a program that is going to plot a function. I
> don't know the correct way to write a matlab function that
> will: 10<=x<=1.2*y (1)
>
> y=3.2
>
> Whenever I type in the code as is, MatLab wants me to
> define x. I am going to put x in another function, ex
> 2.7+x=t. I am going to plot x vs. t. I just don't know how
> to tell MatLab to take values in between the range of the
> above stated values in equation (1).

If y=3.2, x cannot be both greater than 10 and less than 1.2*3.2, can
it?????

In article <fb5j2h$2n2$1@fred.mathworks.com>, jr147@msstate.edu says...
> I am writing a program that is going to plot a function. I
> don't know the correct way to write a matlab function that
> will: 10<=x<=1.2*y (1)
>
> y=3.2
>
> Whenever I type in the code as is, MatLab wants me to
> define x. I am going to put x in another function, ex
> 2.7+x=t. I am going to plot x vs. t. I just don't know how
> to tell MatLab to take values in between the range of the
> above stated values in equation (1).
>

Perhaps an anonymous function will help... It requires that y be
defined in advance, but not x.

between = @(x) (x >= 10) & (x < 1.2*y)

then use

x = 1:20
out = between(x)
and you will get a logical vector saying where the conditions are true
and not.

--
Loren
http://blogs.mathworks.com/loren/

Loren Shure <loren@mathworks.com> wrote in message
<MPG.214081424ffda7f9897ad@news.mathworks.com>...
> In article <fb5j2h$2n2$1@fred.mathworks.com>,
jr147@msstate.edu says...
> > I am writing a program that is going to plot a
function. I
> > don't know the correct way to write a matlab function
that
> > will: 10<=x<=1.2*y (1)
> >
> > y=3.2
> >
> > Whenever I type in the code as is, MatLab wants me to
> > define x. I am going to put x in another function, ex
> > 2.7+x=t. I am going to plot x vs. t. I just don't know
how
> > to tell MatLab to take values in between the range of
the
> > above stated values in equation (1).
> >
>
> Perhaps an anonymous function will help... It requires
that y be
> defined in advance, but not x.
>
> between = @(x) (x >= 10) & (x < 1.2*y)
>
> then use
>
> x = 1:20
> out = between(x)
> and you will get a logical vector saying where the
conditions are true
> and not.
>
> --
> Loren
> http://blogs.mathworks.com/loren/


"x=1:20"

Does this code mean that MatLab is taken values for x at
20 equal increments?

Ender wrote:
...
> "x=1:20"
>
> Does this code mean that MatLab is taken values for x at
> 20 equal increments?

help colon

In article <fb70j0$mr6$1@fred.mathworks.com>, Ender <jr147@msstate.edu> wrote:

>"x=1:20"

>Does this code mean that MatLab is taken values for x at
>20 equal increments?

No, it means that x is taken to be the vector containing the
numbers 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19

x=1:3:20

would be [1 4 7 10 13 16 19]

that is, if you have X:Y then you get a vector containing
X X+1 X+2 X+3 and so on with the last element being the
greatest X+integer that is less than or equal to Y;

if you have X:S:Y then you get a vector containing
X X+S X+2*S X+3*S X+4*S and so on with the last element
being the greatest X+S*integer that is less than or equal to Y.

--
  If you lie to the compiler, it will get its revenge. -- Henry Spencer

"Ender " <jr147@msstate.edu> wrote in news:fb5j2h$2n2$1@fred.mathworks.com:

> I am writing a program that is going to plot a function. I
> don't know the correct way to write a matlab function that
> will: 10<=x<=1.2*y (1)
>
> y=3.2
>
> Whenever I type in the code as is, MatLab wants me to
> define x. I am going to put x in another function, ex
> 2.7+x=t. I am going to plot x vs. t. I just don't know how
> to tell MatLab to take values in between the range of the
> above stated values in equation (1).


You should really read the Getting Started section.


--
Scott
Reverse name to reply

In article <fb70j0$mr6$1@fred.mathworks.com>, jr147@msstate.edu says...
> Loren Shure <loren@mathworks.com> wrote in message
> <MPG.214081424ffda7f9897ad@news.mathworks.com>...
> > In article <fb5j2h$2n2$1@fred.mathworks.com>,
> jr147@msstate.edu says...
> > > I am writing a program that is going to plot a
> function. I
> > > don't know the correct way to write a matlab function
> that
> > > will: 10<=x<=1.2*y (1)
> > >
> > > y=3.2
> > >
> > > Whenever I type in the code as is, MatLab wants me to
> > > define x. I am going to put x in another function, ex
> > > 2.7+x=t. I am going to plot x vs. t. I just don't know
> how
> > > to tell MatLab to take values in between the range of
> the
> > > above stated values in equation (1).
> > >
> >
> > Perhaps an anonymous function will help... It requires
> that y be
> > defined in advance, but not x.
> >
> > between = @(x) (x >= 10) & (x < 1.2*y)
> >
> > then use
> >
> > x = 1:20
> > out = between(x)
> > and you will get a logical vector saying where the
> conditions are true
> > and not.
> >
> > --
> > Loren
> > http://blogs.mathworks.com/loren/
>
>
> "x=1:20"
>
> Does this code mean that MatLab is taken values for x at
> 20 equal increments?
>
>

Yes. Perhaps you'd find it valuable to read the Getting Started section
of the documentation:

http://www.mathworks.com/access/helpdesk/help/techdoc/learn_matlab/bqr_
2pl.html


--
Loren
http://blogs.mathworks.com/loren/

Loren Shure <loren@mathworks.com> wrote in message
<MPG.2140d13018f6f7989897af@news.mathworks.com>...
> In article <fb70j0$mr6$1@fred.mathworks.com>,
jr147@msstate.edu says...
> > Loren Shure <loren@mathworks.com> wrote in message
> > <MPG.214081424ffda7f9897ad@news.mathworks.com>...
> > > In article <fb5j2h$2n2$1@fred.mathworks.com>,
> > jr147@msstate.edu says...
> > > > I am writing a program that is going to plot a
> > function. I
> > > > don't know the correct way to write a matlab
function
> > that
> > > > will: 10<=x<=1.2*y (1)
> > > >
> > > > y=3.2
> > > >
> > > > Whenever I type in the code as is, MatLab wants me
to
> > > > define x. I am going to put x in another function,
ex
> > > > 2.7+x=t. I am going to plot x vs. t. I just don't
know
> > how
> > > > to tell MatLab to take values in between the range
of
> > the
> > > > above stated values in equation (1).
> > > >
> > >
> > > Perhaps an anonymous function will help... It
requires
> > that y be
> > > defined in advance, but not x.
> > >
> > > between = @(x) (x >= 10) & (x < 1.2*y)
> > >
> > > then use
> > >
> > > x = 1:20
> > > out = between(x)
> > > and you will get a logical vector saying where the
> > conditions are true
> > > and not.
> > >
> > > --
> > > Loren
> > > http://blogs.mathworks.com/loren/
> >
> >
> > "x=1:20"
> >
> > Does this code mean that MatLab is taken values for x
at
> > 20 equal increments?
> >
> >
>
> Yes. Perhaps you'd find it valuable to read the Getting
Started section
> of the documentation:
>
>
http://www.mathworks.com/access/helpdesk/help/techdoc/learn
_matlab/bqr_
> 2pl.html
>
>
> --
> Loren
> http://blogs.mathworks.com/loren/


I tried to access the getting started section but the page
didn't display.
I have a question and maybe I didn't phrase what I wanted
properly. I am trying to take values from 10<=x<=46.75 I
want to make an (i) iteration loop that will take values
at specified increments between 10 and 30. I plan on
stating x(i) within this loop. How do I do this?

I tried to accomplish the above stated task this way, but
it didn't work. I wrote code that looked vary similiar to
this

for i=10:1:46.75
    x(i)=10*i
    y(i)=3+x(i)
end

I then plotted a graph in Excel to show my results.
Whenever I try to change the "1" to "0.001" to get a more
refined value in my graph. MatLab gave me this answer.

??? Attempted to access sig_AL_cr(0.001); index must be a
positive integer or logical

I don't know why?
    

"Ender " <jr147@msstate.edu> writes:

> I tried to access the getting started section but the page
> didn't display.
> I have a question and maybe I didn't phrase what I wanted
> properly. I am trying to take values from 10<=x<=46.75 I
> want to make an (i) iteration loop that will take values
> at specified increments between 10 and 30. I plan on
> stating x(i) within this loop. How do I do this?
>
> I tried to accomplish the above stated task this way, but
> it didn't work. I wrote code that looked vary similiar to
> this
>
> for i=10:1:46.75
> x(i)=10*i
> y(i)=3+x(i)
> end
>
> I then plotted a graph in Excel to show my results.
> Whenever I try to change the "1" to "0.001" to get a more
> refined value in my graph. MatLab gave me this answer.
>
> ??? Attempted to access sig_AL_cr(0.001); index must be a
> positive integer or logical

Ah. That's a well-phrased question.

x(i) is an array reference. i is an index. An index has to be an
integer > 0. (What is the 0.5 number in an array?)

A common coding pattern for what you want is this:

x = 10:.001:46.75;

for i=1:length(x)
  y(i) = 3 + 10*x(i);
end

Of course, this is MATLAB, so you can compute simple operations like
that without a loop.

x = 10:.001:46.75;
y = 3 + 10.*x;

And you REALLY need to read the Getting Started section. I guess
Loren's URL was wrapped (thanks to the brand new Forum software).
Just go to the main MATLAB documentation page and click to Getting
Started.

http://www.mathworks.com/access/helpdesk/help/techdoc/


-Peter