Thread Subject: get colormap without generating a figure?

I use this:

map = colormap;

but a blank figure is created. Is there a way to stop that?

Thanks,
David

"David Doria" <daviddoria@gmail.com> wrote in message
news:fducta$hm$1@fred.mathworks.com...
>I use this:
>
> map = colormap;
>
> but a blank figure is created. Is there a way to stop that?

The COLORMAP function, called with that syntax, retrieves the Colormap
property of the current figure. If you do not have a figure open, COLORMAP
will create one for you and return that figure's Colormap property. If you
don't want it to do this, make sure you have a figure open when you call
COLORMAP. Also, you should make sure that the HandleVisible property of
your figure is set so that you can access the handle of the current figure
from wherever you're calling COLORMAP.

http://www.mathworks.com/access/helpdesk/help/techdoc/ref/figure_props.html#HandleVisibility

--
Steve Lord
slord@mathworks.com

I see. I also didn't realize the "maps" were actually
functions, so I can do

a=jet;

and then access the colors in order through a(N, :)

Thanks for the help!

David

"Steven Lord" <slord@mathworks.com> wrote in message
<fduvee$ll6$1@fred.mathworks.com>...
>
> "David Doria" <daviddoria@gmail.com> wrote in message
> news:fducta$hm$1@fred.mathworks.com...
> >I use this:
> >
> > map = colormap;
> >
> > but a blank figure is created. Is there a way to stop that?
>
> The COLORMAP function, called with that syntax, retrieves
the Colormap
> property of the current figure. If you do not have a
figure open, COLORMAP
> will create one for you and return that figure's Colormap
property. If you
> don't want it to do this, make sure you have a figure open
when you call
> COLORMAP. Also, you should make sure that the
HandleVisible property of
> your figure is set so that you can access the handle of
the current figure
> from wherever you're calling COLORMAP.
>
>
http://www.mathworks.com/access/helpdesk/help/techdoc/ref/figure_props.html#HandleVisibility
>
> --
> Steve Lord
> slord@mathworks.com
>
>