Thread Subject: cell array deleting columns without using cellfun

Hallo,
I am working with an old version of Matlab (V6). There the
function cellfun is not yet implemented. So the consequence
is the following problem:

I have a cell array which look like this

value_tag_coding_for_columns =

     [] []
     [] []
    'C' [1x23 char]
    'D' [1x23 char]

How can I delete the rows 1 and 2 without using cellfun?

If I would do it with cellfun then with the following
commands:

toBeDeleted=[cellfun(@isempty,value_tag_coding_for_columns
(1:size(value_tag_coding_for_columns,1)-1,size
(value_tag_coding_for_columns,2)));false];
value_tag_coding_for_columns(toBeDeleted,:)=[]


Thanks, Corinna

Sorry, I meant deleting rows.

But the solution for deleting columns in cells without
cellfun usage would be nice.

Thanks, Corinna

"Corinna Schmitt" <csc@mathworks.com> wrote in message
<fiek2b$rg0$1@fred.mathworks.com>...
> Sorry, I meant deleting rows.
>
> But the solution for deleting columns in cells without
> cellfun usage would be nice.
>
> Thanks, Corinna
>

You don' want using for loop?

Bruno

Hallo Bruno,
> You don' want using for loop?

Ok, for a first step I accept for-loops. But how is then
the solution?

Thanks, Corinna

"Corinna Schmitt" <csc@mathworks.com> wrote in message
<fienbm$g2g$1@fred.mathworks.com>...
> Hallo Bruno,
> > You don' want using for loop?
>
> Ok, for a first step I accept for-loops. But how is then
> the solution?
>
> Thanks, Corinna
>

The only thing one need to pay attention is the loop must
run in reverse, so that there is no delete side effect from
one iteration to the next.

I let you treat the special last-row case as your original
code suggested:

for nrow=size(value_tag_coding_for_columns,1):-1:1
    if isempty(value_tag_coding_for_columns{nrow,end})
        value_tag_coding_for_columns(nrow,:)=[];
    end
end

Bruno