Thread Subject: How to set a value to a group of gui object in a smple way?

Dear all
I want to set a group of menu object's 'label' value in terms of my
requirement.
Below is an example code to illustrate my question.
% begin
LabelCell = {'Name'; 'Score'; 'Class'; 'Age'};
hm = [ 1.111, 2.222, 3.333, 4.444] % all the value is a handle to
a menu object.
for k = 1:numel(hm)
    set(hm(k), 'label', LabelCell{k});
end
% finished

In this way, I can carry my points. However, I think 'for-loop' maybe
replaced and I hope that can be realized in a more simple way. Any
idea about it?

Best Regards
damayi
2007-12-28

damayi <damayi@gmail.com> wrote in message <a57b1eb8-2471-
465d-a144-bca8660c3464@l6g2000prm.googlegroups.com>...
> Dear all
> I want to set a group of menu object's 'label' value in
terms of my
> requirement.
> Below is an example code to illustrate my question.
> % begin
> LabelCell = {'Name'; 'Score'; 'Class'; 'Age'};
> hm = [ 1.111, 2.222, 3.333, 4.444] % all the value is
a handle to
> a menu object.
> for k = 1:numel(hm)
> set(hm(k), 'label', LabelCell{k});
> end
> % finished
>
> In this way, I can carry my points. However, I think 'for-
loop' maybe
> replaced and I hope that can be realized in a more simple
way. Any
> idea about it?
>
> Best Regards
> damayi
> 2007-12-28


arrayfun(@(h,newlab) set(h,'Label',newlab{1}), hm,LabelCell)


Anh Huy Phan
RIKEN - BSI

On Dec 29, 12:01=A0am, "Huy " <phananh...@mathworks.com> wrote:
> damayi <dam...@gmail.com> wrote in message <a57b1eb8-2471-
>
> 465d-a144-bca8660c3...@l6g2000prm.googlegroups.com>...
>
>
>
>
>
> > Dear all
> > I want to set a group of menu object's 'label' value in
> terms of my
> > requirement.
> > Below is an example code to illustrate my question.
> > % begin
> > LabelCell =3D {'Name'; 'Score'; 'Class'; 'Age'};
> > hm =3D [ 1.111, =A02.222, =A03.333, =A04.444] =A0% all the value is
> a handle to
> > a menu object.
> > for k =3D 1:numel(hm)
> > =A0 =A0 set(hm(k), 'label', LabelCell{k});
> > end
> > % finished
>
> > In this way, I can carry my points. However, I think 'for-
> loop' maybe
> > replaced and I hope that can be realized in a more simple
> way. Any
> > idea about it?
>
> > Best Regards
> > damayi
> > 2007-12-28
>
> arrayfun(@(h,newlab) set(h,'Label',newlab{1}), hm,LabelCell)
>
> Anh Huy Phan
> RIKEN - BSI- Hide quoted text -
>
> - Show quoted text -

Thanks for your help. your solution is so simple.
Meanwhile, I compare two solutions and I found that the former is more
efficient or less time cost.
tic; run1 toc; tic; run2; toc

Elapsed time is 0.001227 seconds.
Elapsed time is 0.002984 seconds.