in matlab, how to get the integration of xf(x) from t1 to t2
where f(x) is a Gaussian (or Normal) density function with
known mean and variance parameters? thanks!
"Jerry " <mricad@yahoo.no000spppam.com> wrote in message
<foau82$cqb$1@fred.mathworks.com>...
> in matlab, how to get the integration of xf(x) from t1 to t2
> where f(x) is a Gaussian (or Normal) density function with
> known mean and variance parameters? thanks!
normcdf, if you have the statistics toolbox.
If not, then its a simple transformation of
erf or erfc.
"John D'Errico" <woodchips@rochester.rr.com> wrote in
message <fob0bi$bar$1@fred.mathworks.com>...
> "Jerry " <mricad@yahoo.no000spppam.com> wrote in message
> <foau82$cqb$1@fred.mathworks.com>...
> > in matlab, how to get the integration of xf(x) from t1 to t2
> > where f(x) is a Gaussian (or Normal) density function with
> > known mean and variance parameters? thanks!
>
> normcdf, if you have the statistics toolbox.
>
> If not, then its a simple transformation of
> erf or erfc.
>
> John
no, please note that "integration of xf(x) from t1 to t2",
it's xf(x), not f(x).
"Jerry " <mricad@yahoo.no000spppam.com> wrote in message <foau82$cqb
$1@fred.mathworks.com>...
> in matlab, how to get the integration of xf(x) from t1 to t2
> where f(x) is a Gaussian (or Normal) density function with
> known mean and variance parameters? thanks!
---------
Write x*f(x) = (x-m)*f(x) + m*f(x), where m is the mean. The first one can be
directly integrated in terms of the exp function, while the second can be
expressed in terms of normcdf or erf.
"Jerry " <mricad@yahoo.no000spppam.com> wrote in message <foau82$cqb
$1@fred.mathworks.com>...
> in matlab, how to get the integration of xf(x) from t1 to t2
> where f(x) is a Gaussian (or Normal) density function with
> known mean and variance parameters? thanks!
---------
Write x*f(x) = (x-m)*f(x) + m*f(x), where m is the mean. The first one can be
directly integrated in terms of the exp function, while the second can be
expressed in terms of normcdf or erf.
"Jerry " <mricad@yahoo.no000spppam.com> wrote in message <foau82$cqb
$1@fred.mathworks.com>...
> in matlab, how to get the integration of xf(x) from t1 to t2
> where f(x) is a Gaussian (or Normal) density function with
> known mean and variance parameters? thanks!
---------
Write x*f(x) = (x-m)*f(x) + m*f(x), where m is the mean. The first one can be
directly integrated in terms of the exp function, while the second can be
expressed in terms of normcdf or erf.
"Jerry " <mricad@yahoo.no000spppam.com> wrote in message <foau82$cqb
$1@fred.mathworks.com>...
> in matlab, how to get the integration of xf(x) from t1 to t2
> where f(x) is a Gaussian (or Normal) density function with
> known mean and variance parameters? thanks!
---------
Write x*f(x) = (x-m)*f(x) + m*f(x), where m is the mean. The first one can be
directly integrated in terms of the exp function, while the second can be
expressed in terms of normcdf or erf.
"Roger Stafford" <ellieandrogerxyzzy@mindspring.com.invalid> wrote in
message <fob85m$ctq$1@fred.mathworks.com>...
> Write x*f(x) = (x-m)*f(x) + m*f(x), where m is the mean. The first one can
be
> directly integrated in terms of the exp function, while the second can be
> expressed in terms of normcdf or erf.
>
> Roger Stafford
-------
I think the Matlab Newsgroup is misbehaving again! I clicked the "Post
Message" button only once, I swear, but got four copies sent anyhow. Let's see
how it behaves this time.
"Roger Stafford"
<ellieandrogerxyzzy@mindspring.com.invalid> wrote in
message <foba8e$rr4$1@fred.mathworks.com>...
> "Roger Stafford"
<ellieandrogerxyzzy@mindspring.com.invalid> wrote in
> message <fob85m$ctq$1@fred.mathworks.com>...
> > Write x*f(x) = (x-m)*f(x) + m*f(x), where m is the
mean. The first one can
> be
> > directly integrated in terms of the exp function,
while the second can be
> > expressed in terms of normcdf or erf.
> >
> > Roger Stafford
> -------
> I think the Matlab Newsgroup is misbehaving again! I
clicked the "Post
> Message" button only once, I swear, but got four copies
sent anyhow. Let's see
> how it behaves this time.
>
> Roger Stafford
>
thanks, Roger. Your method is really smart! my OP got a
duplication too, don't worry about it. thanks again.
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