Thread Subject: finding a value from to points on a graph ...

Subject: finding a value from to points on a graph ...

From: Michael Rosgaard

Date: 30 Apr, 2008 08:55:10

Message: 1 of 5

Hey
I got a graph thats look likes this:
http://img246.imageshack.us/my.php?image=graph1qp7.jpg

I want to find the value on the y axis, where there on the x axis is 0.1 distance from 1 place on the graph to another place with a straight line. Like i manually did on the picture.
Hope anyone understand me, and can help :)
Thanks
Rosgaard

Subject: finding a value from to points on a graph ...

From: alessandro mura

Date: 30 Apr, 2008 09:32:42

Message: 2 of 5

This routine extracts data from a jpg image
http://pptt4.ifsi-roma.inaf.it/~mura/matlab/extract_curve.m


--
Alessandro Mura
Istituto Nazionale di Astrofisica - IFSI
http://pptt4.ifsi-roma.inaf.it/~mura/index.html
http://www.alessandromura.it


Subject: finding a value from to points on a graph ...

From: Rosgaard

Date: 13 May, 2008 09:50:52

Message: 3 of 5

that was not was i have in mind...

i got the matlab code to make the plot?

Subject: finding a value from to points on a graph ...

From: us

Date: 13 May, 2008 10:26:04

Message: 4 of 5

Rosgaard:
<SNIP hiding his/her pet...

> i got the matlab code to make the plot...

well, if you show your code answers might(!) come your
way...

us

Subject: finding a value from to points on a graph ...

From: Rosgaard

Date: 14 May, 2008 07:40:27

Message: 5 of 5

i just thought he misunderstood my question, but here it is.

mis1_mean = [0.16119 0.11736 0.089477 0.071339 0.059131 0.050575 0.044319 0.039554...
     0.035784 0.032699 0.030099 0.02785 0.025862 0.024073 0.022437 0.020923 0.019506...
     0.018167 0.016894 0.015674 0.014501 0.013366 0.012265 0.011193 0.010146 0.0091224...
    0.0081182 0.0071319 0.0061616 0.0052058 0.0042631 0.0033323 0.0024126 0.001503 0.00060266...
  -0.00028898 -0.0011726 -0.0020486 -0.0029176 -0.0037801 -0.0046363 -0.0054867 -0.0063315...
   -0.0071711 -0.0080057 -0.0088356 -0.009661 -0.010482 -0.011299 -0.012112 -0.012921...
    -0.013727 -0.014529 -0.015328 -0.016124 -0.016916 -0.017706 -0.018492 -0.019276...
    -0.020057 -0.020836 -0.021612 -0.022385 -0.023156]';
vds=[0.06:0.01:0.69]';
semilogy(vds,abs(mis1_mean)),grid,ylabel('in procent (%)'),xlabel('vds')

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