Thread Subject: how to interchange the locations of value in two strings

for example i have two strings of number

a=[1 2 3 4 5] and b=[6 7 8 9 10]

the problem is how could i change value 3 of a with value
8 of b.its means i interchange the locations 3 and 8 where
the result will become

a=[1 2 8 4 5]
b=[6 7 3 9 10]

before that which column need to be interchange will be
chosen randomly..

"NohaiddaSariff aida":
<SNIP swapping evergreen...

> a=[1 2 3 4 5] and b=[6 7 8 9 10]
> the result will become
> a=[1 2 8 4 5]
> b=[6 7 3 9 10]

one of the many solutions

     a=1:5;
     b=6:10;
     n=4;
     [a(n),b(n)]=deal(b(n),a(n))
%{
     a = 1 2 3 9 5
     b = 6 7 8 4 10
%}

us

"NohaiddaSariff aida" <nohaiddasariff@yahoo.com> wrote in
message <fv9ila$s2v$1@fred.mathworks.com>...
> for example i have two strings of number
>
> a=[1 2 3 4 5] and b=[6 7 8 9 10]
>
> the problem is how could i change value 3 of a with value
> 8 of b.its means i interchange the locations 3 and 8
where
> the result will become
>
> a=[1 2 8 4 5]
> b=[6 7 3 9 10]
>
> before that which column need to be interchange will be
> chosen randomly..

This is too easy ... What have you tried so far yourself?
How would do it by hand?

Jos

"us ":
<SNIP down to incomplete post...

> [a(n),b(n)]=deal(b(n),a(n))

% -or- create a more convenient macro
     swapval=@(n,x,y) deal(y(n),x(n));
     a=1:5;
     b=11:15;
     n=[1,4];
     [a(n),b(n)]=swapval(n,a,b)
% a = 11 2 3 14 5
% b = 1 12 13 4 15

us