Thread Subject: shifting data within a vector

For a vector s, I found its maximum value, and located it

s=rand(20,1);
max(s);
find(s==max(s));


Now I want to add a value of say x=10; to the max(s) and
place it in the following row(raw after max(s)), then add
a value of 20 to the max(s)and add it to the following
raw....etc till the end raw?

Any suggestions?

"Hydroman S" <amirgsalem@gmail.com> wrote in message <fvo3dr$8qk
$1@fred.mathworks.com>...
> For a vector s, I found its maximum value, and located it
>
> s=rand(20,1);
> max(s);
> find(s==max(s));
>
>
> Now I want to add a value of say x=10; to the max(s) and
> place it in the following row(raw after max(s)), then add
> a value of 20 to the max(s)and add it to the following
> raw....etc till the end raw?
>
> Any suggestions?
-----------
  First of all, you don't need 'find' here. Just use the index returned by max:

 [mx,ix] = max(s); % ix is the index of the maximum element of x

  The rest of what you are asking is rather hard to interpret. Your misuse of
the word 'raw' is confusing! My guess is that, starting with ix+1, you wish to
place mx+10, mx+20, ..., in ix+1, ix+2, etc., on to the end of s. Is that it?

 s(ix+1:end) = mx+(10:10:10*(length(s)-ix))';

Roger Stafford

"Roger Stafford" <ellieandrogerxyzzy@mindspring.com.invalid> wrote in
message <fvo564$i8p$1@fred.mathworks.com>...
> First of all, you don't need 'find' here. Just use the index returned by max:
>
> [mx,ix] = max(s); % ix is the index of the maximum element of x
>
> The rest of what you are asking is rather hard to interpret. Your misuse
of
> the word 'raw' is confusing! My guess is that, starting with ix+1, you wish
to
> place mx+10, mx+20, ..., in ix+1, ix+2, etc., on to the end of s. Is that it?
>
> s(ix+1:end) = mx+(10:10:10*(length(s)-ix))';
>
> Roger Stafford
-------
  After looking at your wordage again, it seems possible that what you
actually want is this:

 [mx,ix] = max(s); % ix is the index of the maximum element of x
 s(ix+1:end) = s(ix+1:end) + mx+(10:10:10*(length(s)-ix))';

Roger Stafford

Thank you Roger. Your first reply answers my question.
Apologies for the ‘raw’ stuff, sometimes this stuff comes
from the gut instead of the brain.

Here is exactly what I wanted to do, and thanks again for
your help:

s=rand(20,1);
[mx,ix] = max(s); % ix is the index of the maximum element
of x
s(ix+1:end) = mx+(10:10:10*(length(s)-ix))';
s(1:ix-1)= mx-(10:10:10*(ix-1))';