Thread Subject: Reversing a row matrix

Hi All,

I need to reverse a matrix as follows:
If x=[1 3 8 20 100 121],

how do I get a matrix

y=[121 100 20 8 3 1]

An answer is needed, please.

Emeka

"Emeka Obe" <obeway@gmail.com> writes:

>Hi All,

>I need to reverse a matrix as follows:
fliplr

Emeka Obe wrote:

> I need to reverse a matrix as follows:
> If x=[1 3 8 20 100 121],

> how do I get a matrix

> y=[121 100 20 8 3 1]

> An answer is needed, please.

r = randperm(length(x));
t1 = x(r);
[t2,t3] = sort(r,'descend');
y = t1(t3);

Emeka Obe wrote:
> Hi All,
>
> I need to reverse a matrix as follows:
> If x=[1 3 8 20 100 121],
>
> how do I get a matrix
>
> y=[121 100 20 8 3 1]
>
> An answer is needed, please.
>
> Emeka

y=x(end:-1:1);

Dan

On Oct 10, 7:56=A0am, "Emeka Obe" <obe...@gmail.com> wrote:
> Hi All,
>
> I need to reverse a matrix as follows:
> If x=3D[1 3 8 20 100 121],
>
> how do I get a matrix
>
> y=3D[121 100 20 8 3 1]
>
> An answer is needed, please.
>
> Emeka

>> x=3D[1 3 8 20 100 121]

x =3D

     1 3 8 20 100 121
>> y =3D fliplr(x)

y =3D

   121 100 20 8 3 1

Hope that helps