Thread Subject: how to sum up a series based on a defined interval

Dear all,

There is a series called "value" and it needs to be sum up based on an interval as below and then print out a new series.
>> value = [1;2;3;4;NaN;6;7;8;9;NaN;11;12;13;NaN;15;16;17;18;19;20;21;22;23;24;25;26;NaN;28;29;30;31]
>> interval=[4;3;4;3;4;3;4;3;3]

For example,
[1;2;3;4] for the 1st accumulation based on the 1st value [4] of interval matrix
[NaN;6;7] for the 2nd accumulation based on the 2nd value [3] of interval matrix
[8;9;NaN;11] for the 3rd accumulation based on the 3rd value [4] of interval matrix
[12;13;NaN] for the 4th accumulation based on the 4th value [3] of interval matrix
:
:
[25;26;NaN;28] for the 8th accumulation based on the 8th value [3] of interval matrix
[29;30;31] for the 9th accumulation based on the 9th value [3] of interval matrix

>> output = a new series after the each accumulations.


Please advice me. Thank you.

Michael

mat2cell(value,interval)




|`mfe||+slve|_i|Vqbrk^rbJ|$$=hq^fl^i^m|^l7`_dblq^Bbeljjl^|k

The length of dailyflux is <3288x1>.

I know I probably mixed up in the length of matrix for mat2cell, but I cannot figure it out how to modify my code.

Will you please give me a hint?
Thanks,
Michael

%%%%%%%%
??? Error using ==> mat2cell at 116
Input arguments, D1 through D2, must sum to each dimension of the input matrix size, [3288
1].

%%%%%%%%
dailyflux_NT=CO2resp_daily_NT_m2
for Year = 2000:2007
days_per_weird_week=[]
    for n = 1:12
        days_per_weird_week = [days_per_weird_week ; 7 ; 7 ; 7 ; 7; rem(eomday(Year, n), 7) ]
    end
end

    ind = find(days_per_weird_week ~= 0)
    days_per_weird_week = days_per_weird_week(ind)
    
    for n = 1:length(days_per_weird_week)
        dailyflux_NT(n)=sum{mat2cell(dailyflux_NT,days_per_weird_week)}
        dailyflux_NT = [dailyflux_NT ; dailyflux_NT(n) / days_per_weird_week(n) * ones(days_per_weird_week(n), 1)]
    end