Thread Subject:

Embedded For Loop?

Lets say I have two arrays:

x = [1 2 3 4 5]
y = [9 8 7 6 5]

How would I write a loop that would solve for

z = x + y

for each different combination of x and y values, i.e
z(1,9) z(2,9) z(3,9)... etc?

Thanks,

Kim

My z array would then be a 5 x 5...

One approach:

x = [1 2 3 4 5];
y = [9 8 7 6 5];
[xx,yy] = meshgrid(x,y);
z = xx+yy

Another:

x = [1 2 3 4 5];
y = [9 8 7 6 5]' ; % Note the transpose
z = x(ones(1,5),:)+y(:,ones(1,5))




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On Mar 11, 3:54=A0pm, Carp Fisher <bm...@gmail.com> wrote:
> My z array would then be a 5 x 5...

People here at CSSM tend to be more helpful if you have had a go at
solving the problem yourself, rather than just asking us to give you
the solution.
Have you had any thoughts about how you might go about it?

Carp Fisher <bmjim@gmail.com> wrote in message <16409623.1236739893454.JavaMail.jakarta@nitrogen.mathforum.org>...
> Lets say I have two arrays:
>
> x = [1 2 3 4 5]
> y = [9 8 7 6 5]
>
> How would I write a loop that would solve for
>
> z = x + y
>
> for each different combination of x and y values, i.e
> z(1,9) z(2,9) z(3,9)... etc?
>
> Thanks,
>
> Kim

  You could also do:

 z = round(log(exp(x.')*exp(y)));

assuming x and y contain only positive integers as in your example. Otherwise remove the 'round' portion.

  To be candid with you, I don't actually recommend this method but only present it here as a curiosity.

Roger Stafford

Awesome! Thanks alot