Thread Subject: I need to find the row which has elements zero '0' and greater than 7 and eliminate that row

I have a matrix

         1 2 7
A= 4 5 6
         1 2 3

I need to find the row which has elements zero '0' and greater than 7 and eliminate that row.

I wrote this piece of code but its not working. Please help me.

function A = properList(A)
[row len] = size(A);
if (A(1,1) == 0)
    A = A(2,:);
    for i=1:len
 if (A(1,i) > 6)
         A = A(2,:);
    else
         A = A(1,:);
     end
end
end

Thanks,
Joe

"Joe Frank" <sascod@gmail.com> wrote in message
> I have a matrix
>
> 1 2 7
> A= 4 5 6
> 1 2 3
>
> I need to find the row which has elements zero '0' and greater than 7 and eliminate that row.




Your requirement is not comprehensible. In plain, understandable English, is this what you mean?

Find the rows of matrix A which have no zeros and at least one element greater than seven. Eliminate all such rows.

For example, it looks like the matrix you have shown will remain unchanged.




EKDbbYLNEHXHDWO<RSbDQDR|bPWKSRiW#iHF(O\Q0KDbbFpRbRDLbRJPDXH

"Matt Fig" <spamanon@yahoo.com> wrote in message <gprv41$qrt$1@fred.mathworks.com>...
> "Joe Frank" <sascod@gmail.com> wrote in message
> > I have a matrix
> >
> > 1 2 7
> > A= 4 5 6
> > 1 2 3
> >
> > I need to find the row which has elements zero '0' and greater than 7 and eliminate that row.
>
>
>
>
> Your requirement is not comprehensible. In plain, understandable English, is this what you mean?
>
> Find the rows of matrix A which have no zeros and at least one element greater than seven. Eliminate all such rows.
>
> For example, it looks like the matrix you have shown will remain unchanged.
>
>
>
>
> EKDbbYLNEHXHDWO<RSbDQDR|bPWKSRiW#iHF(O\Q0KDbbFpRbRDLbRJPDXH

I am sorry for the confusion. I need to check the first row of matrix 'A' if it contains either '0' or any number greater than '7' and if it contains them then we have to remove that row from the matrix.

Thanks

Well a straightforward approach would be to use a simple If statement.

if any(A(1,:)==0 | A(1,:)>7)
   A = A(2:end,:)
end

"Matt Fig" <spamanon@yahoo.com> wrote in message <gps35e$8bo$1@fred.mathworks.com>...
> Well a straightforward approach would be to use a simple If statement.
>
> if any(A(1,:)==0 | A(1,:)>7)
> A = A(2:end,:)
> end

Thanks