Thread Subject: Finding indices

I am having trouble with part of a project and need some help.
Lets just say i have a matrix m=[1,3,5;4,5,6]
I need to find the row and column where the matrix equals 5 first. The answer in this case would be row 2 column 2, but i cannot use the find function to do this.

Ive tried using [r,c]=m==5 but it says too many output arguments.

Thanks for the help.

"matthew mccarthy" <batter8@aol.com> wrote in message <gt3s4m$cfv$1@fred.mathworks.com>...
> I am having trouble with part of a project and need some help.
> Lets just say i have a matrix m=[1,3,5;4,5,6]
> I need to find the row and column where the matrix equals 5 first. The answer in this case would be row 2 column 2, but i cannot use the find function to do this.
>
> Ive tried using [r,c]=m==5 but it says too many output arguments.
>
> Thanks for the help.

What is wrong with

[r, c] = find (m == 5)

Joerg

"matthew mccarthy" <batter8@aol.com> wrote in message <gt3s4m$cfv$1@fred.mathworks.com>...
> I am having trouble with part of a project and need some help.
> Lets just say i have a matrix m=[1,3,5;4,5,6]
> I need to find the row and column where the matrix equals 5 first. The answer in this case would be row 2 column 2, but i cannot use the find function to do this.
>
> Ive tried using [r,c]=m==5 but it says too many output arguments.
>
> Thanks for the help.

Why can't you use FIND

[r,c] = find(m==5)
[minC,idx] = min(c)
minR = r(idx)

without FIND you can use logical indexing

[r,c] = meshgrid(1:size(m,1),1:size(m,2)) ;
q = m == 5 ;
r = r(q)
c = c(q)
% etc.

Jos

"Joerg Buchholz" <buchholz@hs-bremen.de> wrote in message <gt3tus$io7$1@fred.mathworks.com>...
> "matthew mccarthy" <batter8@aol.com> wrote in message <gt3s4m$cfv$1@fred.mathworks.com>...
> > I am having trouble with part of a project and need some help.
> > Lets just say i have a matrix m=[1,3,5;4,5,6]
> > I need to find the row and column where the matrix equals 5 first. The answer in this case would be row 2 column 2, but i cannot use the find function to do this.
> >
> > Ive tried using [r,c]=m==5 but it says too many output arguments.
> >
> > Thanks for the help.
>
> What is wrong with
>
> [r, c] = find (m == 5)
>
> Joerg

Just to add to this .... if you want to find the first 5 ... you can use find() like this:
find(m==5, 1, 'first')

"matthew mccarthy" <batter8@aol.com> wrote in message <gt3s4m$cfv$1@fred.mathworks.com>...
> I am having trouble with part of a project and need some help.
> Lets just say i have a matrix m=[1,3,5;4,5,6]
> I need to find the row and column where the matrix equals 5 first. The answer in this case would be row 2 column 2, but i cannot use the find function to do this.
>
> Ive tried using [r,c]=m==5 but it says too many output arguments.
>
> Thanks for the help.
Well its for a project and it states that we are not allowed to use the find function or basically any other functions and implicit loops.
I think its because we just learned the if, for, and while loops and she wants us to use them

"matthew mccarthy" <batter8@aol.com> wrote in message <gt3s4m$cfv$1@fred.mathworks.com>...
> I am having trouble with part of a project and need some help.
> Lets just say i have a matrix m=[1,3,5;4,5,6]
> I need to find the row and column where the matrix equals 5 first. The answer in this case would be row 2 column 2, but i cannot use the find function to do this.
>
> Ive tried using [r,c]=m==5 but it says too many output arguments.
>
> Thanks for the help.

In part we need to know what YOU mean by "equals 5 first." Do you count rows first or columns first? For example, where is the first 5 in [1 5;5 1]? Once you define that, you can use or modify this horrible construct:


m=[1,3,5;4,5,6]

for ii = 1:2 % I assume you cannot use size either?
    for jj = 1:3
        if m(ii,jj)==5
            r = ii;
            c = jj;
        end
    end
end

well we already have the dimensions i just made up a problem for the sake of me not having to type out the whole project.
I just read some more instructions and it says we have to perform a row-wise search.
So we look at the first row first and if the value is not found then we got to the next row and so on.
So actually the answer would be row 1 column 3.
Ive been trying to figure this out and i just have no clue