Thread Subject: structure array in a for

Hi there!

In a function we are using the following:

for i=1:100

Struct(i) = func2(var1);

end

where func2 is defined in the following way:
function [outp] = func2(input);

where outp is a structure, i.e. for i=1 outp.field=20, outp.field2=40,
etc.....
                                           for i=2 outp.field=30,
outp.field2=50
we would like to store in each step of the loop the variable outp as
an structure cell inside the variable Struct.

Hence, Struct(1).field=20,Struct(1).field2=40
           Struct(2).field=30,Struct(2).field2=50

Do you have any hint? How do we need to define the variables?

The only solution found has been passing the i and the Struct variable
in the function itself as an input and output,
i.e. Struct = func2(var1,Struct,i); and function [output]=func2
(input,Struct,i); but is not very elegant.

Any help on this matter would be very much appreciated!

Thanks a lot,

Enric and Pep

I tried this with the call to func2(var1) inside the for loop and it works fine.
What are you trying to do inside func2. I tried a simple struct assignment like this -

for i=1:100
Struct(i) = func2(i);
end

where I defined func2 as -

function outp = func2(value)
outp.field1=value *10;
outp.field2 = value +10;

Each scalar struct passed back by func2 is assigned to the struct array inside the loop. Depending on your need, there might be other better ways of doing what you want , but the above method is correct as well.

John thanks a lot for your reply.

However, this is not working for us since you are passing the i
parameter of the for into the function as a value. This is precisely
what we wanted to avoid.

Notice that our func2 is independent of the looping parameters and it
depends on other values.

Kind regards,

Enric and Pep


On 12 Juny, 20:22, "John" <sj...@cnbc.cmu.edu> wrote:
> I tried this with the call to func2(var1) inside the for loop and it works fine.
> What are you trying to do inside func2. I tried a simple struct assignment like this -
>
> for i=1:100
> Struct(i) = func2(i);
> end
>
> where I defined func2 as -
>
> function outp = func2(value)
> outp.field1=value *10;
> outp.field2 = value +10;
>
> Each scalar struct passed back by func2 is assigned to the struct array inside the loop. Depending on your need, there might be other better ways of doing what you want , but the above method is correct as well.

Enric, I passed the loop counter into func2 only as an example. It does not matter how you assign values to outp struct variable inside func2. You can call func2 with any input parameters.

enric <e.girones@gmail.com> wrote in message <4399128a-090e-44de-9cc7-f3bea7910f6d@a7g2000yqk.googlegroups.com>...
> John thanks a lot for your reply.
>
> However, this is not working for us since you are passing the i
> parameter of the for into the function as a value. This is precisely
> what we wanted to avoid.
>
> Notice that our func2 is independent of the looping parameters and it
> depends on other values.
>
> Kind regards,
>
> Enric and Pep
>
>
> On 12 Juny, 20:22, "John" <sj...@cnbc.cmu.edu> wrote:
> > I tried this with the call to func2(var1) inside the for loop and it works fine.
> > What are you trying to do inside func2. I tried a simple struct assignment like this -
> >
> > for i=1:100
> > Struct(i) = func2(i);
> > end
> >
> > where I defined func2 as -
> >
> > function outp = func2(value)
> > outp.field1=value *10;
> > outp.field2 = value +10;
> >
> > Each scalar struct passed back by func2 is assigned to the struct array inside the loop. Depending on your need, there might be other better ways of doing what you want , but the above method is correct as well.