Thread Subject: hist

I was wondering whether it is possible to run the hist command over the marix rows.
for instance if A=[10 9 8 12 20 21 30 18]
then h=hist(A) will be [3 1 0 0 1 2 0 0 0 1].

Now imagine that A=[10 9 8 12 20 21 30 18;...
                               11 21 1 17 15 11 29 8]
I was wondering whether there is a way to get the hist of this matrix over the element of the rows which for instance in this case give the following result
[3 1 0 0 1 2 0 0 0 1;...
 1 0 1 2 1 1 0 1 0 1]
Thanks in advance for the help

On Oct 26, 12:28 pm, "SM " <khanmor...@gmail.com> wrote:
> I was wondering whether it is possible to run the hist command over the marix rows.
> for instance if A=[10 9 8 12 20 21 30 18]
> then h=hist(A) will be  [3     1     0     0     1     2     0     0     0     1].
>
> Now imagine that A=[10 9 8 12 20 21 30 18;...
>                                11 21 1 17 15 11 29 8]
> I was wondering whether there is a way to get the hist of this matrix over the element of the rows which for instance in this case give the following result
> [3     1     0     0     1     2     0     0     0     1;...
>  1     0     1     2     1     1     0     1     0     1]
> Thanks in advance for the help

how about a for loop?

for n=1:size(A,1)
  h(n,:) = hist(A(n,:));
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
h =
     3 1 0 0 1 2 0 0 0 1
     1 0 1 2 1 1 0 1 0 1

-Nathan

"SM " <khanmoradi@gmail.com> wrote in message <hc4t82$b15$1@fred.mathworks.com>...
> I was wondering whether it is possible to run the hist command over the marix rows.
> for instance if A=[10 9 8 12 20 21 30 18]
> then h=hist(A) will be [3 1 0 0 1 2 0 0 0 1].
>
> Now imagine that A=[10 9 8 12 20 21 30 18;...
> 11 21 1 17 15 11 29 8]
> I was wondering whether there is a way to get the hist of this matrix over the element of the rows which for instance in this case give the following result
> [3 1 0 0 1 2 0 0 0 1;...
> 1 0 1 2 1 1 0 1 0 1]
> Thanks in advance for the help

I don't think there is a one-liner that will do that, but you can just loop over the rows:

>> for nr = 1:size(A,1),
>> h{nr} = hist(A(nr,:))
>> end

Note that I used a cell array to store the results of each HIST command. There are other possibilities.

the cyclist

SM wrote:
> I was wondering whether it is possible to run the hist command over the marix rows.
...
>
> Now imagine that A=[10 9 8 12 20 21 30 18;...
> 11 21 1 17 15 11 29 8]
> I was wondering whether there is a way to get the hist of this matrix
> over the element of the rows ...

n = hist(A');

--

dpb <none@non.net> wrote in message <hc4u3o$inq$1@news.eternal-september.org>...
> SM wrote:
> > I was wondering whether it is possible to run the hist command over the marix rows.
> ...
> >
> > Now imagine that A=[10 9 8 12 20 21 30 18;...
> > 11 21 1 17 15 11 29 8]
> > I was wondering whether there is a way to get the hist of this matrix
> > over the element of the rows ...
>
> n = hist(A');
>
> --

This is a way to do it as a one-liner, but note that this does NOT give the same result as doing them independently via a loop, because the matrix method uses a common binning for all histograms. This is apparently what the OP wants to avoid.

the cyclist

Thanks guys,
I have one more thing to ask...I also want to define some discard level which is the the most repeated value in each row. For this I am trying to take the maximum occurence of the hist in each row and then find its corresponding value!
But I recieve a dimension mismatch error.
Can you help me with this as well.
Thanks again

"SM " <khanmoradi@gmail.com> wrote in message <hc50qh$ge9$1@fred.mathworks.com>...
> Thanks guys,
> I have one more thing to ask...I also want to define some discard level which is the the most repeated value in each row. For this I am trying to take the maximum occurence of the hist in each row and then find its corresponding value!
> But I recieve a dimension mismatch error.
> Can you help me with this as well.
> Thanks again

In principle, you could use HIST for this, but I would explore the MODE command. If you putter around and cannot figure it out, show us what you have done, and we can try to help some more.

the cyclist