Thread Subject: function handle evaluation

Hi,

lets say: f = @(x,y) sin(x*y)

i want to evaluate at x = 1, y = pi/2, All i will do f(1,pi/2) and get the correct answer.

What if a = [1 pi/2] and type f(a), then the second argument is not defined and it errors out. So, is there a way i can pass in the input argument without explicitly writing it out. I am evaluating a function handle in a for loop where the values are changing every step. The values are getting called frrom a matrix generated based on some user input. So i dont know the value apriori.

f = @(x,y) sin(x*y) ;
a = [1 pi/2];

f(a(1),a(2))

hi try this
>> f=@(x)sin(x(1)*x(2))

f =
    @(x)sin(x(1)*x(2))

>> a=[1 pi/2]

a =

    1.0000 1.5708

>> f(a)

ans =

     1