Thread Subject: Basic PED boundary condition

Subject: Basic PED boundary condition

From: Sang

Date: 20 Nov, 2009 22:26:03

Message: 1 of 1

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HI~
I am beginner... I couldn't find any source.

For left boundary condition, du/dx=0
For right boundary condition, du/dx=-1.5

function [pl,ql,pr,qr] = pdex1bc (xl,ul,xr,ur,t);
pl = 0;
ql = 1;
pr = ?
qr = ?

What do I have to wirte for each term of pr and qr?
Thank you in advance.

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