Eamonn B wrote:
> I have a vector set up like this
> a = [[5 2 1 4 8]' [6 3 10 3 -5]']; % [x] [y]
> I want to delete the x and y at the same time
> I am able to show the two indices by doing this
> [a(2,1) a(2,2)]
> I try and delete them by doing this [a(2,1) a(2,2)]=
> I get this error
> 'Too many output arguments.'
> I have also tried this way
> z=[a(2,1) a(2,2)]
> it works a=1 5 8 10 3 3 6 -5
> but it removes the columns thus putting the x and y together which is
> not what I want.
> Anyone know how I can remove the value but still keeping the columns?
The problem in general is that if you try to remove
more-or-less-randomly placed elements in an array, the array is no
longer square--hence the result above of a vector returned.
You could set elements to zero but to make them null either would
require a cell array or regularizing the elements to be eliminated.
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