Thread Subject:

Space one array and other questions

Hi,

i will use this topic to some question about the work I'm doing. (encoding code words of block linear)

1st I have this code to generate an array with all possibility of binary combinations:

for i=1:2^k
m(1,1:k)=dec2bin(0,k);
m(i,1:k)=dec2bin(i-1,k);
end


I want one space between each bit... how can i do it?

Thank you in advance

it's urgent

Nobody knows?

fckool wrote:
> it's urgent

Best be getting busy then, I reckon...

> Nobody knows?

Only that I know I don't understand the question.

Give an example of what you mean by a space between each bit...if you
mean you want character representation, something like

sprintf('%c %c %c \n',m')

might suit. If you have something else in mind, I'll have to wait until
the crystal comes back from the shop (again)...

--

fckool wrote:

> 1st I have this code to generate an array with all possibility of binary combinations:
>
> for i=1:2^k
> m(1,1:k)=dec2bin(0,k);
> m(i,1:k)=dec2bin(i-1,k);
> end

> I want one space between each bit... how can i do it?

Start by fixing your code. Every iteration of the array, you write over
m(1,1:k) with '0', which is not necessary because when "i" is 1, you store
that same value in the same location.

 > It's urgent

m = repmat(' ', 2^k, 2*k-1);
for i = 1 : 2^k
m(i,1:2:2*k-1) = dec2bin(i-1,k);
end

what is the difference between that code and this one?:

for i = 1:2^k
        for j = k:-1:1
            if rem(i-1,2^(-j+k+1))>=2^(-j+k)
                m1(i,j)=1;
            else
                m1(i,j)=0;
            end
        end
   end

after this I want do this:

c=mod(m*G,2)
´
but it give me an error:
??? Error using ==> mtimes
Inner matrix dimensions must agree.

G it's an array calculated before this.

fckool wrote:

> c=mod(m*G,2)
> ´
> but it give me an error:
> ??? Error using ==> mtimes
> Inner matrix dimensions must agree.
>
> G it's an array calculated before this.


* is the Matrix Multiplication operator. As per usual, m*G is only possible if
the second dimension of m is the same as the first dimension of G. If you want
to multiply each corresponding element of m by each corresponding element of
G, then use m .* G .

By the way, watch out for m1 versas m .

fckool wrote:
...

> c=mod(m*G,2)
> ´
> but it give me an error:
> ??? Error using ==> mtimes
> Inner matrix dimensions must agree.
>
> G it's an array calculated before this.

Well, "*" is matrix multiplication in Matlab so one must have conformant
array sizes for the operation as defined by matrix operations.

If G is same dimensions as m and you mean element-wise mulitplication,
that's ".*" in Matlab

doc times
doc mtimes

--

with the code that I showed you, it works... but I cant use it.. I have to use another one..

Your code maybe not work because when you add a space (string value?) you are increasing the array dim, not?

who can I separate the bits, for a better read, without increase its size?

fckool wrote:

> Your code maybe not work because when you add a space (string value?) you are increasing the array dim, not?

It does increase the dimensions, but that isn't necessarily a problem.

> who can I separate the bits, for a better read, without increase its size?

m = repmat(' ', 2^k, k);
for i = 1 : 2^k
m(i,:) = dec2bin(i-1,k);
end

mdisplay = repmat(' ', 2^k, 2*k-1);
mdisplay(:,1:2:2*k-1) = m;


Or, if you prefer an expression over efficiency,

mdisplay = cell2mat(arrayfun(@(c) [c ' '], m, 'Uniform',0))

perfect, know it works.

I have to explain every line of my program can you to explain this 2 lines please?:

mdisplay = repmat(' ', 2^k, 2*k-1);
mdisplay(:,1:2:2*k-1) = m;

The efficient expression it's very good but I never gonna get it explains by myself lol..


I have another question:

how can I test the efficiency of my code? (how much time it need to run)


thank you very much, and i apology if I'm being boring.

fckool <xtrangekid@sapo.pt> wrote in message <1706344931.315227.1276210722145.JavaMail.root@gallium.mathforum.org>...
> perfect, know it works.
>
> I have to explain every line of my program can you to explain this 2 lines please?:
>
> mdisplay = repmat(' ', 2^k, 2*k-1);
> mdisplay(:,1:2:2*k-1) = m;
>
> The efficient expression it's very good but I never gonna get it explains by myself lol..
>
>
> I have another question:
>
> how can I test the efficiency of my code? (how much time it need to run)
>
>
> thank you very much, and i apology if I'm being boring.

To understand the code you can highlight in the m-file the sigle parts and execute it. Another thing you can do is to place the cursor on the function and press F1 or type in the command propmt "doc repmat".

Example:
repmat(' ', 2^k, 2*k-1);
Start by higlighting "2*k-1" execute it...If k = 3 then the expression evaluates to 3.

then you can mentally rewrite the expression as:
repmat(' ',4,3) --> repeat the ' ' (blank) for 4 rows and 3 columns.

To measure the performance of your code you can read in the help about the profiler.

Oleg

Walter Roberson <roberson@hushmail.com> wrote in message <hurmm4$32t$1@canopus.cc.umanitoba.ca>...
> fckool wrote:
>
> > Your code maybe not work because when you add a space (string value?) you are increasing the array dim, not?
>
> It does increase the dimensions, but that isn't necessarily a problem.
>
> > who can I separate the bits, for a better read, without increase its size?
>
> m = repmat(' ', 2^k, k);
> for i = 1 : 2^k
> m(i,:) = dec2bin(i-1,k);
> end

DEC2BIN is vectorized, so you can skip the for-loop:

k = 3 ;
m = dec2bin(0:2^k-1,k)

Jos

thank you for teach me to use the help.

It was more easy try explain it than try to teach me how to use the help.

I already tried to use it..


If everybody could know everything with the help, the forum would not make sense, but ok thank you anyway.

you are right, but in that way I cant have a space between each value in the array.

Thank you for the advice