"Haris Hameed" <harishameed_33@hotmail.com> wrote in message <hviv81$o75$1@fred.mathworks.com>...
> The surface area (As) of a taper cylinder is
> As= pi*(d1+d2)/2*L
> d1= diameter of right face
> d2= diameter of left face
> L= length of taper cone
> Similarly surface area for any type of such surface will be
> As= (p1+p2)/2*L
> Where, p1=perimeter of right face
> P2= perimeter of left face
> In the above two cases the two faces are connected by a tapered (inclined) but a straight line
> So my question is how to fine the surface area if the two faces are joined by a curve
> For above case we can write in integration form As= int(p(x) dx)
> int= integral
> what will be P(x) in case of curved surface.
        
This is more properly a question in elementary calculus and not in matlab. However, the area of a surface of revolution is given by
A = integral 2*pi*f(x)*sqrt(1+(f'(x)^2) dx
where x is the distance along the central axis of revolution and f(x) is the orthogonal distance from that axis to the surface. This f(x) would be equal to your P(x)/(2*pi), and dx would be your dL/sqrt(1+(f'(x)^2)).
Roger Stafford
