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"deepak " <dkjknobel@rediff.com> wrote in message <i07kj4$phq$1@fred.mathworks.com>...
> I have two odes as
>
> K(l-(x2-x1-l)/cos(a2))*cos(a2) -c(x2'-x1')=((x1’’*cos(2*a2 - a1))/2 + 2*g*sin(a1) + 12*x1’’*cos(a1) + 2*g*sin(a1 - 2*a2) - (5*x1’’*cos(a1 - 2*a2))/2 - 2*x1’’*cos(a1 + 2*a2))/(4*(cos(2*a1) + cos(2*a2) - cos(2*a1 - 2*a2)/2 - cos(2*a1 + 2*a2)/2 + 3)) + cot(a2)/(cos(a1)*(1/sin(a2)^2 + cot(a2)^2/cos(a1)^2 + cot(a2)^2*tan(a1)^2 + 1)^(1/2))
>
> and,
>
> K(l-(x1-x3)/cos(a2))*cos(a2) -c(x1'-x3')=1/(sin(a2)*(1/sin(a2)^2 + cos(a2)^2/(cos(a1)^2*sin(a2)^2) + (cos(a2)^2*sin(a1)^2)/(cos(a1)^2*sin(a2)^2) + 1)^(1/2)) - (2*g*sin(a2) - 12*x1’’*(2*sin(a2/2)^2 - 1) - 2*g*sin(2*a1 - a2) + 2*x1’’*(2*sin(a1 - a2/2)^2 - 1) + 2*x1’’*(2*sin(a1 + a2/2)^2 - 1))/(4*(sin(a1 + a2)^2 - 2*sin(a1)^2 - 2*sin(a2)^2 + sin(a1 - a2)^2 + 4))
>
> where
> g=9.8m/s^2
> x3'= constant and known
> and a1 and a2 are known as well.
> so there are 6 unknown x1,x2,x3 and x1',x2' and x3'' and two second order odes.
>
> Now you can see that converting it into system of nice looking single order odes is tough. is there any way i can solve it without doing that or how can i convert it into system of single order odes
>
> Thanks
Oh Gosh
U have no idea it seems flooding NEWSREADER..
Send me your equation in written or latex file and tell me which variables are of your interest. I hope i will be able to put it into nice looking ode.
Regards,
Faraz
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