Thread Subject: How do you find all the 0's in a matrix and replace with NaN

Could someone tell me how to search for all the zero's in a martix and then replace it wirh NaN ?

say:
x = [1 1 1 0; 1 1 0 0; 0 0 0 0; 1 1 0 1; 0 0 1 1]

x =

     1 1 1 0
     1 1 0 0
     0 0 0 0
     1 1 0 1
     0 0 1 1

I can find the 0 using

 find(x == 0)

ans =

     3
     5
     8
    10
    12
    13
    14
    16
    17
    18

But how do I replace these values ?

I'm sorry if similar questions have been answered, but I could only find examples of replacing NaNs with numbers or integers.

x(x==0)=nan

ImageAnalyst wrote:
> x(x==0)=nan

x(~x)=nan; % :p

Brilliant thanks !!!!!!