Thread Subject: crosstab

Subject: crosstab

From: Arthur Zheng

Date: 2 Sep, 2010 04:29:04

Message: 1 of 1

[table,chi2,p] = crosstab(...) also returns the chi-square statistic chi2 and its p-value p for a test that table is independent in each dimension. The null hypothesis is that the proportion in any entry of table is the product of the proportions in each dimension.

What test does crosstab use? chi square test? Fisher's exact test?
Thanks.

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