Hi John!
Hey! Yes it does work.
Actually, it was my mistake. I need a plane parallel to the line joining the two points. So the normal to that plane wont be [1,0,0], right? Because the y and z coordinates are different. Had one of them be the same then that would have worked out, I guess.
But, I want a plane parallel to the line joining the two points.
How to go about it?
Appreciate your response.
Thanks,
Gaurav
"John D'Errico" <woodchips@rochester.rr.com> wrote in message <ig639q$76v$1@fred.mathworks.com>...
> "GAURAV " <gsharda@engineering.uiowa.edu> wrote in message <ig60su$2i9$1@fred.mathworks.com>...
> > Hi!
> >
> > I have two points 3D coordinates [794, 782, 885] and [794, 814, 868]. What will be the equation of the plane passing through these two points in 3D space i.e. effectively a line through this point and extended parallely to form a plane? Here, the x coordinate is constant. i.e. a plane parallel to the yz view.
> >
> > What will be the point and the normal coordinates for the points?
> >
> > Would it be any one point for the point and normal [794,0,0]?? It doesnot quite work out though.
>
> There are infinitely many planes through these two points.
>
> If you wish to find the plane that is parallel to the yz plane,
> where x = 794, then an arbitrary point in that plane is
>
> [794 0 0 ]
>
> and the normal vector to that plane will indeed be
>
> [1 0 0]
>
> So what does not work out?
>
> John
