Thread Subject:

reshaping array

Hello,

I have an array:

A=['A1' 'A2' 'A3' 'A4' 'A5' 'A6' 'A7' 'A8' ]
want to create another array B=['A2A1' 'A4A3' 'A6A5' 'A8A7']

is it possible to do this with the reshape command?. If not how to implement this?

On 2/3/2012 12:11 PM, Leyo Joseph wrote:
> Hello,
>
> I have an array:
>
> A=['A1' 'A2' 'A3' 'A4' 'A5' 'A6' 'A7' 'A8' ]
> want to create another array B=['A2A1' 'A4A3' 'A6A5' 'A8A7']
>
> is it possible to do this with the reshape command?. If not how to
> implement this?

It doesn't occur to me otomh altho I won't say "no"...

I'd brute-force it...

for idx=1:4:length(A)-4
   b(idx:idx+1)=A(idx+2:idx+3);
   b(idx+2:idx+3)=A(idx:idx+1);
end

--

"Leyo Joseph" wrote in message <jgh80h$m6h$1@newscl01ah.mathworks.com>...
> Hello,
>
> I have an array:
>
> A=['A1' 'A2' 'A3' 'A4' 'A5' 'A6' 'A7' 'A8' ]
> want to create another array B=['A2A1' 'A4A3' 'A6A5' 'A8A7']
>
> is it possible to do this with the reshape command?. If not how to implement this?
- - - - - - - -
  The answer to your first question is 'no'. The '8' character must always remain at the end under reshaping (and under transposing as well.)

  For the second question an alternative without for-loops is:

 n = 0:length(A)-1;
 B = A(3+n+2*(mod(n,2)-mod(n,4)));

Roger Stafford

On 2/3/2012 1:50 PM, Roger Stafford wrote:
...

> For the second question an alternative without

[explicit]

> for-loops is:

<VBG>

--

I suppose if you're really determined to use reshape (and to be completely inefficient and unclear to boot)

a = ['A1' 'A2' 'A3' 'A4' 'A5' 'A6' 'A7' 'A8' ];
b = regexprep( reshape( fliplr( reshape(strrep(a, 'A', ''), [], 4) .' ) .', 1, [] ), '(\d)', 'A$1' )